Tangent lines to circles

In Euclidean plane geometry, a tangent line to a circle is a line that touches the circle at exactly one point, never entering the circle's interior. Tangent lines to circles form the subject of several theorems, and play an important role in many geometrical constructions and proofs. Since the tangent line to a circle at a point Template:Mvar is perpendicular to the radius to that point, theorems involving tangent lines often involve radial lines and orthogonal circles.

Tangent lines to one circle

A tangent line Template:Mvar to a circle Template:Mvar intersects the circle at a single point Template:Mvar. For comparison, secant lines intersect a circle at two points, whereas another line may not intersect a circle at all. This property of tangent lines is preserved under many geometrical transformations, such as scalings, rotation, translations, inversions, and map projections. In technical language, these transformations do not change the incidence structure of the tangent line and circle, even though the line and circle may be deformed.

The radius of a circle is perpendicular to the tangent line through its endpoint on the circle's circumference. Conversely, the perpendicular to a radius through the same endpoint is a tangent line. The resulting geometrical figure of circle and tangent line has a reflection symmetry about the axis of the radius.

File:Power point simple.svg

By the power-of-a-point theorem, the product of lengths Template:Mvar for any ray Template:Mvar equals the square of Template:Mvar, the length of the tangent line segment (red).

No tangent line can be drawn through a point within a circle, since any such line must be a secant line. However, two tangent lines can be drawn to a circle from a point Template:Mvar outside of the circle. The geometrical figure of a circle and both tangent lines likewise has a reflection symmetry about the radial axis joining Template:Mvar to the center point Template:Mvar of the circle. Thus the lengths of the segments from Template:Mvar to the two tangent points are equal (this is sometimes called the Two Tangents Theorem, see Incircle). By the secant-tangent theorem, the square of this tangent length equals the power of the point P in the circle Template:Mvar. This power equals the product of distances from Template:Mvar to any two intersection points of the circle with a secant line passing through Template:Mvar.

File:Inscribed angle theorem4.svg

The angle Template:Mvar between a chord and a tangent is half the arc belonging to the chord.

The tangent line Template:Mvar and the tangent point Template:Mvar have a conjugate relationship to one another, which has been generalized into the idea of pole points and polar lines. The same reciprocal relation exists between a point Template:Mvar outside the circle and the secant line joining its two points of tangency.

If a point Template:Mvar is exterior to a circle with center Template:Mvar, and if the tangent lines from Template:Mvar touch the circle at points Template:Mvar and Template:Mvar, then ∠TPS and ∠TOS are supplementary (sum to 180°).

If a chord Template:Mvar is drawn from the tangency point Template:Mvar of exterior point Template:Mvar and ∠PTM ≤ 90° then ∠PTM = ½ ∠TOM.

Cartesian equation

Suppose that the equation of the circle in Cartesian coordinates is $(x-a{)}^2+(y-b{)}^2=r^2$ with center at (a, b). Then the tangent line of the circle at (x₁, y₁) has Cartesian equation

$$(x-x_1)(x_1-a)+(y-y_1)(y_1-b)=0$$

This can be proved by taking the implicit derivative of the circle. Say that the circle has equation of $(x-a{)}^2+(y-b{)}^2=r^2,$ and we are finding the slope of tangent line at (x₁, y₁) where $(x_1-a{)}^2+(y_1-b{)}^2=r^2.$ We begin by taking the implicit derivative with respect to Template:Mvar:

$$\begin{array}{rl}\stackrel{}{(}x-a{)}^2+(y-b{)}^2& =r^2\\ 2(x-a)+2(y-b)\frac{dy}{dx}& =0\\ \frac{dy}{dx}& =-\frac{x_1-a}{y_1-b}\end{array}$$

Now that we have the slope of the tangent line, we can substitute the slope and the coordinate of the tangency point into the line equation y = kx + m.

$$\begin{array}{rl}y& =-\frac{x_1-a}{y_1-b}x+y_1+x_1\frac{x_1-a}{y_1-b}\\ y-y_1& =(x_1-x)\frac{x_1-a}{y_1-b}\\ (y-y_1)(y_1-b)& =-(x-x_1)(x_1-a)\\ (x-x_1)(x_1-a)+(y-y_1)(y_1-b)& =0\end{array}$$

Compass and straightedge constructions

It is relatively straightforward to construct a line Template:Mvar tangent to a circle at a point Template:Mvar on the circumference of the circle:

• A line Template:Mvar is drawn from Template:Mvar, the center of the circle, through the radial point Template:Mvar;
• The line Template:Mvar is the perpendicular line to Template:Mvar.

File:Tangent from exterior point to circle construction.svg

Construction of tangent lines to a circle (Template:Mvar) from a given exterior point (Template:Mvar).

Thales' theorem may be used to construct the tangent lines to a point Template:Mvar external to the circle Template:Mvar:

• A circle is drawn centered on the midpoint Template:Mvar of the line segment Template:Mvar, having diameter Template:Mvar, where Template:Mvar is again the center of the circle Template:Mvar (cyan).
• The intersection points T₁ and T₂ of the circle Template:Mvar and the new circle are the tangent points for lines passing through Template:Mvar, by the following argument (tan).

The line segments OT₁ and OT₂ are radii of the circle Template:Mvar; since both are inscribed in a semicircle, they are perpendicular to the line segments PT₁ and PT₂, respectively. But only a tangent line is perpendicular to the radial line. Hence, the two lines from Template:Mvar and passing through T₁ and T₂ are tangent to the circle Template:Mvar.

Another method to construct the tangent lines to a point Template:Mvar external to the circle using only a straightedge:

• Draw any three different lines through the given point Template:Mvar that intersect the circle twice.
• Let A₁, A₂, B₁, B₂, C₁, C₂ be the six intersection points, with the same letter corresponding to the same line and the index 1 corresponding to the point closer to Template:Mvar.
• Let Template:Mvar be the point where the lines A₁B₂ and A₂B₁ intersect,
• Similarly Template:Mvar for the lines B₁C₂ and B₂C₁.
• Draw a line through Template:Mvar and Template:Mvar.
• This line meets the circle at two points, Template:Mvar and Template:Mvar.
• The tangents are the lines Template:Mvar and Template:Mvar.

With analytic geometry

Let $P=(a,b)$ be a point of the circle with equation $x^2+y^2=r^2.$ The tangent at Template:Mvar has equation $ax+by=r^2,$ because Template:Mvar lies on both the curves and $\overrightarrow{OP}=(a,b{)}^T$ is a normal vector of the line. The tangent intersects the Template:Mvar-axis at point $P_0=(x_0,0)$ with $a{x}_0=r^2.$

File:Kreistangenten-p0.svg

Tangents through a point

Conversely, if one starts with point $P_0=(x_0,0),$ then the two tangents through P₀ meet the circle at the two points $P_{1/2}=(a,b_{\pm })$ with $$a=\frac{r^2}{x_0},b_{\pm }=\pm \sqrt{r^2-a^2}=\pm \frac{r}{x_0}\sqrt{x_0^2-r^2}.$$ Written in vector form: $$(\genfrac{}{}{0ex}{}{a}{b_{\pm }})=\frac{r^2}{x_0}(\genfrac{}{}{0ex}{}{1}{0})\pm \frac{r}{x_0}\sqrt{x_0^2-r^2}(\genfrac{}{}{0ex}{}{0}{1}).$$

If point $P_0=(x_0,y_0)$ lies not on the Template:Mvar-axis: In the vector form one replaces x₀ by the distance $d_0=\sqrt{x_0^2+y_0^2}$ and the unit base vectors by the orthogonal unit vectors ${\overrightarrow{e}}_1=\frac{1}{d_0}(\genfrac{}{}{0ex}{}{x_0}{y_0}),{\overrightarrow{e}}_2=\frac{1}{d_0}(\genfrac{}{}{0ex}{}{-y_0}{x_0}).$ Then the tangents through point P₀ touch the circle at the points $$(\genfrac{}{}{0ex}{}{x_{1/2}}{y_{1/2}})=\frac{r^2}{d_0^2}(\genfrac{}{}{0ex}{}{x_0}{y_0})\pm \frac{r}{d_0^2}\sqrt{d_0^2-r^2}(\genfrac{}{}{0ex}{}{-y_0}{x_0}).$$

• For d₀ < r no tangents exist.
• For d₀ = r point P₀ lies on the circle and there is just one tangent with equation $x_{0}x+y_{0}y=r^2.$
• In case of d₀ > r there are 2 tangents with equations $x_{1}x+y_{1}y=r^2,x_{2}x+y_{2}y=r^2.$

Relation to circle inversion: Equation $a{x}_0=r^2$ describes the circle inversion of point $(x_0,0).$

Relation to pole and polar: The polar of point $(x_0,0)$ has equation $x{x}_0=r^2.$

Tangential polygons

A tangential polygon is a polygon each of whose sides is tangent to a particular circle, called its incircle. Every triangle is a tangential polygon, as is every regular polygon of any number of sides; in addition, for every number of polygon sides there are an infinite number of non-congruent tangential polygons.

Tangent quadrilateral theorem and inscribed circles

A tangential quadrilateral Template:Mvar is a closed figure of four straight sides that are tangent to a given circle Template:Mvar. Equivalently, the circle Template:Mvar is inscribed in the quadrilateral Template:Mvar. By the Pitot theorem, the sums of opposite sides of any such quadrilateral are equal, i.e.,

$$\overline{AB}+\overline{CD}=\overline{BC}+\overline{DA}.$$

File:Pitot theorem.svg

Tangential quadrilateral

This conclusion follows from the equality of the tangent segments from the four vertices of the quadrilateral. Let the tangent points be denoted as Template:Mvar (on segment Template:Mvar), Template:Mvar (on segment Template:Mvar), Template:Mvar (on segment Template:Mvar) and Template:Mvar (on segment Template:Mvar). The symmetric tangent segments about each point of Template:Mvar are equal: $$\begin{array}{rl}\overline{BP}=\overline{BQ}=b,& \overline{CQ}=\overline{CR}=c,\\ \overline{DR}=\overline{DS}=d,& \overline{AS}=\overline{AP}=a.\end{array}$$ But each side of the quadrilateral is composed of two such tangent segments

$$\begin{array}{rl}& \overline{AB}+\overline{CD}=(a+b)+(c+d)\\ =& \overline{BC}+\overline{DA}=(b+c)+(d+a)\end{array}$$

proving the theorem.

The converse is also true: a circle can be inscribed into every quadrilateral in which the lengths of opposite sides sum to the same value.

This theorem and its converse have various uses. For example, they show immediately that no rectangle can have an inscribed circle unless it is a square, and that every rhombus has an inscribed circle, whereas a general parallelogram does not.

Tangent lines to two circles

File:Tangenten an kreise streckzentrum.svg

The external (above) and internal (below) homothetic center Template:Mvar of the two circles.

For two circles, there are generally four distinct lines that are tangent to both (bitangent) – if the two circles are outside each other – but in degenerate cases there may be any number between zero and four bitangent lines; these are addressed below. For two of these, the external tangent lines, the circles fall on the same side of the line; for the two others, the internal tangent lines, the circles fall on opposite sides of the line. The external tangent lines intersect in the external homothetic center, whereas the internal tangent lines intersect at the internal homothetic center. Both the external and internal homothetic centers lie on the line of centers (the line connecting the centers of the two circles), closer to the center of the smaller circle: the internal center is in the segment between the two circles, while the external center is not between the points, but rather outside, on the side of the center of the smaller circle. If the two circles have equal radius, there are still four bitangents, but the external tangent lines are parallel and there is no external center in the affine plane; in the projective plane, the external homothetic center lies at the point at infinity corresponding to the slope of these lines.

Outer tangent

File:Aeussere tangente computation.svg

Finding outer tangent. Two circles' outer tangents.

The red line joining the points (x₃, y₃) and (x₄, y₄) is the outer tangent between the two circles. Given points (x₁, y₁), (x₂, y₂) the points (x₃, y₃), (x₄, y₄) can easily be calculated with help of the angle Template:Mvar:

$$\begin{array}{rl}{x}_3& =x_1\pm r\sin \alpha \\ y_3& =y_1\pm r\cos \alpha \\ x_4& =x_2\pm R\sin \alpha \\ y_4& =y_2\pm R\cos \alpha \\ \end{array}$$

Here Template:Mvar and Template:Mvar notate the radii of the two circles and the angle Template:Mvar can be computed using basic trigonometry. You have α = γ − β with $$\begin{array}{rl}\gamma & =-\text{atan2}(y_2-y_1,x_2-x_1)\\ \beta & =\pm \arcsin \left(\frac{R-r}{\sqrt{(x_2-x_1{)}^2+(y_2-y_1{)}^2}}\right)\end{array}$$ where atan2 the 2-argument arctangent.

File:Aeussere tangente.svg

Outer tangents to two circles

The distances between the centers of the nearer and farther circles, O₂ and O₁ and the point where the two outer tangents of the two circles intersect (homothetic center), Template:Mvar respectively can be found out using similarity as follows: $$\frac{dr}{r_1-r_2}$$ Here, Template:Mvar can be r₁ or r₂ depending upon the need to find distances from the centers of the nearer or farther circle, O₂ and O₁. Template:Mvar is the distance O₁O₂ between the centers of two circles.

Inner tangent

File:Inner tangent1.svg

Inner tangent. The external tangent lines pass through the internal homothetic center.

An inner tangent is a tangent that intersects the segment joining two circles' centers. Note that the inner tangent will not be defined for cases when the two circles overlap.

Construction

The bitangent lines can be constructed either by constructing the homothetic centers, as described at that article, and then constructing the tangent lines through the homothetic center that is tangent to one circle, by one of the methods described above. The resulting line will then be tangent to the other circle as well. Alternatively, the tangent lines and tangent points can be constructed more directly, as detailed below. Note that in degenerate cases these constructions break down; to simplify exposition this is not discussed in this section, but a form of the construction can work in limit cases (e.g., two circles tangent at one point).

Synthetic geometry

Let O₁ and O₂ be the centers of the two circles, C₁ and C₂ and let r₁ and r₂ be their radii, with r₁ > r₂; in other words, circle C₁ is defined as the larger of the two circles. Two different methods may be used to construct the external and internal tangent lines.

External tangents

File:Aeussere tangente.svg

Construction of the outer tangent

A new circle C₃ of radius r₁ − r₂ is drawn centered on O₁. Using the method above, two lines are drawn from O₂ that are tangent to this new circle. These lines are parallel to the desired tangent lines, because the situation corresponds to shrinking both circles C₁ and C₂ by a constant amount, r₂, which shrinks C₂ to a point. Two radial lines may be drawn from the center O₁ through the tangent points on C₃; these intersect C₁ at the desired tangent points. The desired external tangent lines are the lines perpendicular to these radial lines at those tangent points, which may be constructed as described above.

Internal tangents

File:Innere tangente.svg

Construction of the inner tangent

A new circle C₃ of radius r₁ + r₂ is drawn centered on O₁. Using the method above, two lines are drawn from O₂ that are tangent to this new circle. These lines are parallel to the desired tangent lines, because the situation corresponds to shrinking C₂ to a point while expanding C₁ by a constant amount, r₂. Two radial lines may be drawn from the center O₁ through the tangent points on C₃; these intersect C₁ at the desired tangent points. The desired internal tangent lines are the lines perpendicular to these radial lines at those tangent points, which may be constructed as described above.

Analytic geometry

Let the circles have centres c₁ = (x₁, y₁) and c₂ = (x₂, y₂) with radius r₁ and r₂ respectively. Expressing a line by the equation $ax+by+c=0,$ with the normalization $a^2+b^2=1,$ then a bitangent line satisfies: $$\begin{array}{rl}a{x}_1+b{y}_1+c& =r_1\\ a{x}_2+b{y}_2+c& =r_2\\ \end{array}$$ Solving for (a, b, c) by subtracting the first from the second yields $$a\mathrm{\Delta }x+b\mathrm{\Delta }y=\mathrm{\Delta }r,(1)$$ where $$\mathrm{\Delta }x=x_2-x_1,\mathrm{\Delta }y=y_2-y_1$$ and $$\mathrm{\Delta }r=r_2-r_1$$ for the outer tangent or $$\mathrm{\Delta }r=r_2+r_1$$ for the inner tangent.

If $d=\sqrt{(\mathrm{\Delta }x{)}^2+(\mathrm{\Delta }y{)}^2}$ is the distance from c₁ to c₂ we can normalize by $$X=\frac{\mathrm{\Delta }x}{d},Y=\frac{\mathrm{\Delta }y}{d},R=\frac{\mathrm{\Delta }r}{d}$$ to simplify equation (1), resulting in the following system of equations: $$\begin{array}{rl}aX+bY& =R,\\ a^2+b^2& =1;\end{array}$$ solve these to get two solutions (k = ±1) for the two external tangent lines: $$\begin{array}{rl}a& =RX-kY\sqrt{1-R^2}\\ b& =RY+kX\sqrt{1-R^2}\\ c& =r_1-(a{x}_1+b{y}_1)\end{array}$$ Geometrically this corresponds to computing the angle formed by the tangent lines and the line of centers, and then using that to rotate the equation for the line of centers to yield an equation for the tangent line. The angle is computed by computing the trigonometric functions of a right triangle whose vertices are the (external) homothetic center, a center of a circle, and a tangent point; the hypotenuse lies on the tangent line, the radius is opposite the angle, and the adjacent side lies on the line of centers.

(X, Y) is the unit vector pointing from c₁ to c₂, while Template:Mvar is cos θ where Template:Mvar is the angle between the line of centers and a tangent line. sin θ is then $\pm \sqrt{1-R^2}$ (depending on the sign of Template:Mvar, equivalently the direction of rotation), and the above equations are rotation of (X, Y) by ±θ using the rotation matrix: $$\left(\begin{array}{cc}R& \mp \sqrt{1-R^2}\\ \pm \sqrt{1-R^2}& R\end{array}\right)$$

• k = 1 is the tangent line to the right of the circles looking from c₁ to c₂.
• k = −1 is the tangent line to the right of the circles looking from c₂ to c₁.

The above assumes each circle has positive radius. If r₁ is positive and r₂ negative then c₁ will lie to the left of each line and c₂ to the right, and the two tangent lines will cross. In this way all four solutions are obtained. Switching signs of both radii switches k = 1 and k = −1.

Vectors

File:Tangent 0.svg

Finding outer tangent. Circle tangents.

In general the points of tangency t₁ and t₂ for the four lines tangent to two circles with centers v₁ and v₂ and radii r₁ and r₂ are given by solving the simultaneous equations:

$$\begin{array}{rl}(t_2-v_2)\cdot (t_2-t_1)& =0\\ (t_1-v_1)\cdot (t_2-t_1)& =0\\ (t_1-v_1)\cdot (t_1-v_1)& =r_1^2\\ (t_2-v_2)\cdot (t_2-v_2)& =r_2^2\\ \end{array}$$

These equations express that the tangent line, which is parallel to $t_2-t_1,$ is perpendicular to the radii, and that the tangent points lie on their respective circles.

These are four quadratic equations in two two-dimensional vector variables, and in general position will have four pairs of solutions.

Degenerate cases

Two distinct circles may have between zero and four bitangent lines, depending on configuration; these can be classified in terms of the distance between the centers and the radii. If counted with multiplicity (counting a common tangent twice) there are zero, two, or four bitangent lines. Bitangent lines can also be generalized to circles with negative or zero radius. The degenerate cases and the multiplicities can also be understood in terms of limits of other configurations – e.g., a limit of two circles that almost touch, and moving one so that they touch, or a circle with small radius shrinking to a circle of zero radius.

• If the circles are outside each other ($d>r_1+r_2$), which is general position, there are four bitangents.
• If they touch externally at one point ($d=r_1+r_2$) – have one point of external tangency – then they have two external bitangents and one internal bitangent, namely the common tangent line. This common tangent line has multiplicity two, as it separates the circles (one on the left, one on the right) for either orientation (direction).
• If the circles intersect in two points ($|r_1-r_2|<d<r_1+r_2$), then they have no internal bitangents and two external bitangents (they cannot be separated, because they intersect, hence no internal bitangents).
• If the circles touch internally at one point ($d=|r_1-r_2|$) – have one point of internal tangency – then they have no internal bitangents and one external bitangent, namely the common tangent line, which has multiplicity two, as above.
• If one circle is completely inside the other ($d<|r_1-r_2|$) then they have no bitangents, as a tangent line to the outer circle does not intersect the inner circle, or conversely a tangent line to the inner circle is a secant line to the outer circle.

Finally, if the two circles are identical, any tangent to the circle is a common tangent and hence (external) bitangent, so there is a circle's worth of bitangents.

Further, the notion of bitangent lines can be extended to circles with negative radius (the same locus of points, $x^2+y^2=(-r{)}^2,$ but considered "inside out"), in which case if the radii have opposite sign (one circle has negative radius and the other has positive radius) the external and internal homothetic centers and external and internal bitangents are switched, while if the radii have the same sign (both positive radii or both negative radii) "external" and "internal" have the same usual sense (switching one sign switches them, so switching both switches them back).

Bitangent lines can also be defined when one or both of the circles has radius zero. In this case the circle with radius zero is a double point, and thus any line passing through it intersects the point with multiplicity two, hence is "tangent". If one circle has radius zero, a bitangent line is simply a line tangent to the circle and passing through the point, and is counted with multiplicity two. If both circles have radius zero, then the bitangent line is the line they define, and is counted with multiplicity four.

Note that in these degenerate cases the external and internal homothetic center do generally still exist (the external center is at infinity if the radii are equal), except if the circles coincide, in which case the external center is not defined, or if both circles have radius zero, in which case the internal center is not defined.

Applications

Belt problem

The internal and external tangent lines are useful in solving the belt problem, which is to calculate the length of a belt or rope needed to fit snugly over two pulleys. If the belt is considered to be a mathematical line of negligible thickness, and if both pulleys are assumed to lie in exactly the same plane, the problem devolves to summing the lengths of the relevant tangent line segments with the lengths of circular arcs subtended by the belt. If the belt is wrapped about the wheels so as to cross, the interior tangent line segments are relevant. Conversely, if the belt is wrapped exteriorly around the pulleys, the exterior tangent line segments are relevant; this case is sometimes called the pulley problem.

Tangent lines to three circles: Monge's theorem

For three circles denoted by C₁, C₂, and C₃, there are three pairs of circles (C₁C₂, C₂C₃, and C₁C₃). Since each pair of circles has two homothetic centers, there are six homothetic centers altogether. Gaspard Monge showed in the early 19th century that these six points lie on four lines, each line having three collinear points.

Problem of Apollonius

File:Apollonius problem animation smaller.gif

Animation showing the inversive transformation of an Apollonius problem. The blue and red circles swell to tangency, and are inverted in the grey circle, producing two straight lines. The yellow solutions are found by sliding a circle between them until it touches the transformed green circle from within or without.

Many special cases of Apollonius's problem involve finding a circle that is tangent to one or more lines. The simplest of these is to construct circles that are tangent to three given lines (the LLL problem). To solve this problem, the center of any such circle must lie on an angle bisector of any pair of the lines; there are two angle-bisecting lines for every intersection of two lines. The intersections of these angle bisectors give the centers of solution circles. There are four such circles in general, the inscribed circle of the triangle formed by the intersection of the three lines, and the three exscribed circles.

A general Apollonius problem can be transformed into the simpler problem of circle tangent to one circle and two parallel lines (itself a special case of the LLC special case). To accomplish this, it suffices to scale two of the three given circles until they just touch, i.e., are tangent. An inversion in their tangent point with respect to a circle of appropriate radius transforms the two touching given circles into two parallel lines, and the third given circle into another circle. Thus, the solutions may be found by sliding a circle of constant radius between two parallel lines until it contacts the transformed third circle. Re-inversion produces the corresponding solutions to the original problem.

Generalizations

File:Pole and polar.svg

The concept of a tangent line and tangent point can be generalized to a pole point Template:Mvar and its corresponding polar line Template:Mvar. The points Template:Mvar and Template:Mvar are inverses of each other with respect to the circle.

The concept of a tangent line to one or more circles can be generalized in several ways. First, the conjugate relationship between tangent points and tangent lines can be generalized to pole points and polar lines, in which the pole points may be anywhere, not only on the circumference of the circle. Second, the union of two circles is a special (reducible) case of a quartic plane curve, and the external and internal tangent lines are the bitangents to this quartic curve. A generic quartic curve has 28 bitangents.

A third generalization considers tangent circles, rather than tangent lines; a tangent line can be considered as a tangent circle of infinite radius. In particular, the external tangent lines to two circles are limiting cases of a family of circles which are internally or externally tangent to both circles, while the internal tangent lines are limiting cases of a family of circles which are internally tangent to one and externally tangent to the other of the two circles.

In Möbius or inversive geometry, lines are viewed as circles through a point "at infinity" and for any line and any circle, there is a Möbius transformation which maps one to the other. In Möbius geometry, tangency between a line and a circle becomes a special case of tangency between two circles. This equivalence is extended further in Lie sphere geometry.

Radius and tangent line are perpendicular at a point of a circle, and hyperbolic-orthogonal at a point of the unit hyperbola. The parametric representation of the unit hyperbola via radius vector is p(a) = (cosh a, sinh a). The derivative of p(a) points in the direction of tangent line at p(a), and is $\frac{dp}{da}=(\sinh a,\cosh a).$ The radius and tangent are hyperbolic orthogonal at Template:Mvar since p(a) and Template:Tmath are reflections of each other in the asymptote y = x of the unit hyperbola. When interpreted as split-complex numbers (where j j = +1), the two numbers satisfy $jp(a)=\frac{dp}{da}.$