Singularity function

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Template:Short description Singularity functions are a class of discontinuous functions that contain singularities, i.e., they are discontinuous at their singular points. Singularity functions have been heavily studied in the field of mathematics under the alternative names of generalized functions and distribution theory.[1][2][3] The functions are notated with brackets, as ⟨x−a⟩n where n is an integer. The "⟨⟩" are often referred to as singularity brackets . The functions are defined as:

n ⟨x−a⟩n
<0 d|n+1|dx|n+1|δ(x−a)
-2 ddxδ(x−a)
-1 δ(x−a)
0 H(x−a)
1 (x−a)H(x−a)
2 (x−a)2H(x−a)
≥0 (x−a)nH(x−a)

where: δ(x)Script error: No such module "Check for unknown parameters". is the Dirac delta function, also called the unit impulse. The first derivative of δ(x)Script error: No such module "Check for unknown parameters". is also called the unit doublet. The function H(x) is the Heaviside step function: H(x) = 0Script error: No such module "Check for unknown parameters". for x < 0Script error: No such module "Check for unknown parameters". and H(x) = 1Script error: No such module "Check for unknown parameters". for x > 0Script error: No such module "Check for unknown parameters".. The value of H(0)Script error: No such module "Check for unknown parameters". will depend upon the particular convention chosen for the Heaviside step function. Note that this will only be an issue for n = 0Script error: No such module "Check for unknown parameters". since the functions contain a multiplicative factor of x − aScript error: No such module "Check for unknown parameters". for n > 0Script error: No such module "Check for unknown parameters".. ⟨x−a⟩1 is also called the Ramp function.

Integration

Integrating ⟨x−a⟩n can be done in a convenient way in which the constant of integration is automatically included so the result will be 0Script error: No such module "Check for unknown parameters". at x = aScript error: No such module "Check for unknown parameters"..

∫⟨x−a⟩ndx={⟨x−a⟩n+1,n<0⟨x−a⟩n+1n+1,n≥0

Example beam calculation

The deflection of a simply supported beam, as shown in the diagram, with constant cross-section and elastic modulus, can be found using Euler–Bernoulli beam theory. Here, we are using the sign convention of downward forces and sagging bending moments being positive.

File:Loaded beam.svg

Load distribution:

w=−3 N⟨x−0⟩−1 + 6 Nm−1⟨x−2 m⟩0 − 9 N⟨x−4 m⟩−1 − 6 Nm−1⟨x−4 m⟩0 

Shear force:

S=∫wdx
S=−3 N⟨x−0⟩0 + 6 Nm−1⟨x−2 m⟩1 − 9 N⟨x−4 m⟩0 − 6 Nm−1⟨x−4 m⟩1

Bending moment:

M=−∫Sdx
M=3 N⟨x−0⟩1 − 3 Nm−1⟨x−2 m⟩2 + 9 N⟨x−4 m⟩1 + 3 Nm−1⟨x−4 m⟩2

Slope:

u′=1EI∫Mdx
Because the slope is not zero at x = 0, a constant of integration, c, is added
u′=1EI(32 N⟨x−0⟩2 − 1 Nm−1⟨x−2 m⟩3 + 92 N⟨x−4 m⟩2 + 1 Nm−1⟨x−4 m⟩3 + c)

Deflection:

u=∫u′dx
u=1EI(12 N⟨x−0⟩3 − 14 Nm−1⟨x−2 m⟩4 + 32 N⟨x−4 m⟩3 + 14 Nm−1⟨x−4 m⟩4 + cx)

The boundary condition u = 0 at x = 4 m allows us to solve for c = −7 Nm2

See also

References

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  1. ↑ Script error: No such module "citation/CS1".
  2. ↑ Script error: No such module "citation/CS1".
  3. ↑ Script error: No such module "citation/CS1".

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External links