Radius of curvature

File:Radius of curvature.svg

Radius of curvature and center of curvature

In differential geometry, the radius of curvature, Template:Mvar, is the reciprocal of the curvature. For a curve, it equals the radius of the circular arc which best approximates the curve at that point. For surfaces, the radius of curvature is the radius of a circle that best fits a normal section or combinations thereof.

Definition

In the case of a space curve, the radius of curvature is the length of the curvature vector.

In the case of a plane curve, then Template:Mvar is the absolute value of

$R\equiv \left|\frac{ds}{d\phi }\right|=\frac{1}{\kappa },$

where Template:Mvar is the arc length from a fixed point on the curve, Template:Mvar is the tangential angle and Template:Mvar is the curvature.

Formula

In two dimensions

If the curve is given in Cartesian coordinates as y(x), i.e., as the graph of a function, then the radius of curvature is (assuming the curve is differentiable up to order 2)

$$R=\left|\frac{{(1+y{\text{'}}^2)}^{\frac{3}{2}}}{y^{″}}\right|,$$

where $y^{\prime }=\frac{dy}{dx},$ $y^{″}=\frac{d^{2}y}{d{x}^2},$ and Template:Abs denotes the absolute value of Template:Mvar.

If the curve is given parametrically by functions x(t) and y(t), then the radius of curvature is

$$R=\left|\frac{ds}{d\phi }\right|=\left|\frac{{\left({\dot{x}}^2+{\dot{y}}^2\right)}^{\frac{3}{2}}}{\dot{x}\ddot{y}-\dot{y}\ddot{x}}\right|$$

where $\dot{x}=\frac{dx}{dt},$ $\ddot{x}=\frac{d^{2}x}{d{t}^2},$ $\dot{y}=\frac{dy}{dt},$ and $\ddot{y}=\frac{d^{2}y}{d{t}^2}.$

Heuristically, this result can be interpreted as

$$R=\frac{{\left|\mathbf{𝐯}\right|}^3}{|\mathbf{𝐯}\times \dot{\mathbf{v}}|},$$

where

$$\left|\mathbf{𝐯}\right|=|(\dot{x},\dot{y})|=R\frac{d\phi }{dt}.$$

In Template:Mvar dimensions

If γ : ℝ → ℝⁿ is a parametrized curve in ℝⁿ then the radius of curvature at each point of the curve, ρ : ℝ → ℝ, is given by

$$\rho =\frac{{\left|{\mathit{\gamma }}^{\prime }\right|}^3}{\sqrt{{\left|{\mathit{\gamma }}^{\prime }\right|}^2{\left|{\mathit{\gamma }}^{″}\right|}^2-{({\mathit{\gamma }}^{\prime }\cdot {\mathit{\gamma }}^{″})}^2}}.$$

As a special case, if f(t) is a function from ℝ to ℝ, then the radius of curvature of its graph, γ(t) = (t, f (t)), is

$$\rho (t)=\frac{{|1+f{\text{'}}^2(t)|}^{\frac{3}{2}}}{|f^{″}(t)|}.$$

Derivation

Let γ be as above, and fix Template:Mvar. We want to find the radius Template:Mvar of a parametrized circle which matches γ in its zeroth, first, and second derivatives at Template:Mvar. Clearly the radius will not depend on the position γ(t), only on the velocity γ′(t) and acceleration γ″(t). There are only three independent scalars that can be obtained from two vectors v and w, namely v · v, v · w, and w · w. Thus the radius of curvature must be a function of the three scalars Template:Abs², Template:Abs² and γ′(t) · γ″(t).

The general equation for a parametrized circle in ℝⁿ is

$$\mathbf{𝐠}(u)=\mathbf{𝐚}\cos (h(u))+\mathbf{𝐛}\sin (h(u))+\mathbf{𝐜}$$

where c ∈ ℝⁿ is the center of the circle (irrelevant since it disappears in the derivatives), a,b ∈ ℝⁿ are perpendicular vectors of length Template:Mvar (that is, a · a = b · b = ρ² and a · b = 0), and h : ℝ → ℝ is an arbitrary function which is twice differentiable at Template:Mvar.

The relevant derivatives of g work out to be

$$\begin{array}{rl}|{\mathbf{𝐠}}^{\prime }{|}^2& ={\rho }^2(h^{\prime }{)}^2\\ {\mathbf{𝐠}}^{\prime }\cdot {\mathbf{𝐠}}^{″}& ={\rho }^2{h}^{\prime }{h}^{″}\\ |{\mathbf{𝐠}}^{″}{|}^2& ={\rho }^2((h^{\prime }{)}^4+(h^{″}{)}^2)\end{array}$$

If we now equate these derivatives of g to the corresponding derivatives of γ at Template:Mvar we obtain

$$\begin{array}{rl}|{\mathit{\gamma }}^{\prime }(t){|}^2& ={\rho }^{2}h{\text{'}}^2(t)\\ {\mathit{\gamma }}^{\prime }(t)\cdot {\mathit{\gamma }}^{″}(t)& ={\rho }^2{h}^{\prime }(t)h^{″}(t)\\ |{\mathit{\gamma }}^{″}(t){|}^2& ={\rho }^2(h{\text{'}}^4(t)+h^{\prime }{\text{'}}^2(t))\end{array}$$

These three equations in three unknowns (Template:Mvar, h′(t) and h″(t)) can be solved for Template:Mvar, giving the formula for the radius of curvature:

$$\rho (t)=\frac{{|{\mathit{\gamma }}^{\prime }(t)|}^3}{\sqrt{{|{\mathit{\gamma }}^{\prime }(t)|}^2{|{\mathit{\gamma }}^{″}(t)|}^2-({\mathit{\gamma }}^{\prime }(t)\cdot {\mathit{\gamma }}^{″}(t){)}^2}},$$

or, omitting the parameter Template:Mvar for readability,

$$\rho =\frac{{\left|{\mathit{\gamma }}^{\prime }\right|}^3}{\sqrt{{\left|{\mathit{\gamma }}^{\prime }\right|}^2{\left|{\mathit{\gamma }}^{″}\right|}^2-{({\mathit{\gamma }}^{\prime }\cdot {\mathit{\gamma }}^{″})}^2}}.$$

Examples

Semicircles and circles

For a semi-circle of radius Template:Mvar in the upper half-plane with $R=|-a|=a,$

$$\begin{array}{rl}y& =\sqrt{a^2-x^2}\\ y^{\prime }& =\frac{-x}{\sqrt{a^2-x^2}}\\ y^{″}& =\frac{-a^2}{{(a^2-x^2)}^{\frac{3}{2}}}.\end{array}$$

For a semi-circle of radius Template:Mvar in the lower half-plane $$y=-\sqrt{a^2-x^2}.$$

The circle of radius Template:Mvar has a radius of curvature equal to Template:Mvar.

Ellipses

File:Ellipse evolute.svg

An ellipse (red) and its evolute (blue). The dots are the vertices of the ellipse, at the points of greatest and least curvature.

In an ellipse with major axis 2a and minor axis 2b, the vertices on the major axis have the smallest radius of curvature of any points, $R=\frac{b^2}{a}$; and the vertices on the minor axis have the largest radius of curvature of any points, R = Template:Sfrac.

The radius of curvature of an ellipse as a function of the geocentric coordinate $t$ with $\tan t=\frac{y}{x}$ is$$R(t)=\frac{(b^2{\cos }^{2}t+a^2{\sin }^{2}t{)}^{3/2}}{ab}.$$It has its minima at $t=0$ and $t=180^{\circ }$ and its maxima at $t=\pm 90^{\circ }$.

Applications

• For the use in differential geometry, see Cesàro equation.
• For the radius of curvature of the Earth (approximated by an oblate ellipsoid); see also: arc measurement
• Radius of curvature is also used in a three part equation for bending of beams.
• Radius of curvature (optics)
• Thin films technologies
• Printed electronics
• Minimum railway curve radius
• AFM probe

Stress in semiconductor structures

Stress in the semiconductor structure involving evaporated thin films usually results from the thermal expansion (thermal stress) during the manufacturing process. Thermal stress occurs because film depositions are usually made above room temperature. Upon cooling from the deposition temperature to room temperature, the difference in the thermal expansion coefficients of the substrate and the film cause thermal stress.

Intrinsic stress results from the microstructure created in the film as atoms are deposited on the substrate. Tensile stress results from microvoids (small holes, considered to be defects) in the thin film, because of the attractive interaction of atoms across the voids.

The stress in thin film semiconductor structures results in the buckling of the wafers. The radius of the curvature of the stressed structure is related to stress tensor in the structure, and can be described by modified Stoney formula. The topography of the stressed structure including radii of curvature can be measured using optical scanner methods. The modern scanner tools have capability to measure full topography of the substrate and to measure both principal radii of curvature, while providing the accuracy of the order of 0.1% for radii of curvature of 90 meters and more.

See also

• Base curve radius
• Bend radius
• Degree of curvature (civil engineering)
• Osculating circle
• Track transition curve

External links

• The Geometry Center: Principal Curvatures
• 15.3 Curvature and Radius of Curvature Template:Webarchive