1956 NBA Finals
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The 1956 NBA World Championship Series was the championship series played at the conclusion of the 1955–56 National Basketball Association (NBA) season. The Philadelphia Warriors defeated the Fort Wayne Pistons four games to one. The series is notable for being one of only two Finals in which the two teams alternated home games, the other being in Template:Nbafy.
Series summary
| Game | Date | Home team | Result | Road team |
|---|---|---|---|---|
| Game 1 | March 31 | Philadelphia Warriors | 99–94 (1–0) | Fort Wayne Pistons |
| Game 2 | April 1 | Fort Wayne Pistons | 84–83 (1–1) | Philadelphia Warriors |
| Game 3 | April 3 | Philadelphia Warriors | 100–96 (2–1) | Fort Wayne Pistons |
| Game 4 | April 5 | Fort Wayne Pistons | 105–107 (1–3) | Philadelphia Warriors |
| Game 5 | April 7 | Philadelphia Warriors | 99–88 (4–1) | Fort Wayne Pistons |
Warriors win series 4–1
Team rosters
Philadelphia Warriors
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Fort Wayne Pistons
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Box scores
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See also
References
- 1955-56 NBA Season Summary, basketball-reference.com. Retrieved March 29, 2014.
External links
Template:NBA Finals Template:Philadelphia Warriors 1955–56 NBA champions Template:Golden State Warriors Template:Detroit Pistons Template:1955–56 NBA season by team Template:NBA on NBC
- 1955–56 NBA season
- NBA Finals
- Philadelphia Warriors games
- Detroit Pistons games
- March 1956 sports events in the United States
- April 1956 sports events in the United States
- Basketball competitions in Philadelphia
- Basketball competitions in Indiana
- 1956 in sports in Indiana
- 1956 in sports in Pennsylvania
- 1950s in Philadelphia
- Sports competitions in Fort Wayne, Indiana