User:Shmigheghi

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This is lame

88632=2πrs3/2428281/2 
Ts=88632
rs=20425.987 km 
vs=krs =4282820425.987 =1.44801 km/s 
ls=rsvs=29577.0886km2s

H=m2⋅kmC2
889258.49=ℓ12/428281+e1cos⁡(2.809) 
582775.22=ℓ12/428281+e1cos⁡(2.759) 
582775.22⋅42828(1+e1cos⁡(2.759))
e1=(889258.49582775.22 −1)cos⁡(2.759)−(889258.49582775.22 cos⁡(2.809)) =1.022>1
ℓ1=35988.1428km2s
ℓ1=krp(1+e1)
krs 
rp=35988.1428242828(2.022) =14955.8095 km 
vp=42828(2.022)41955.8095 =2.4063 km/s 
Mh=−F+esinh⁡(F)=k2(e2−1)3/2tℓ3 
tanh⁡(F/2)=1.022−11.022+1 tan⁡(2.7592 )=0.53861
F=2(arctanh(0.53861))=1.2044
t=938221.1669 s
Mh=0.008492
0=esinh⁡(F)−F−Mh
Fn+1=Fn−esinh⁡(Fn)−Fn−Mhecosh⁡(Fn)−1 
F1=0.2
F2=0.2−1.022sinh⁡(0.2)−0.2−0.0084921.022cosh⁡(0.2)−1 =0.264143
F3=0.25603217
F4=0.25587253
tanh⁡(0.2558722 )=1.022−11.022+1 tan⁡(ϕ/2)
ϕ=1.76824 rad
r=ℓ2/k1+ecos⁡(ϕ) =37823.45092 km
e2=rs−rprs+rp =0.154604
ℓ2=2krsrprs+rp =27194.7733 km2s
Δv1=krp (2rsrs+rp −1+e1)=−0.587957 km/s
T2=2πk (rs+rp2 )3/2=2π42828(20425.987+14955.80952 )3/2 
T2=71439.893 seconds
T22=35719.95 seconds
Δv2=krs (1−2rprs+rp )=4282820425.987 (1−2(14955.8095)20425.987+14955.8095 )
Δv2=0.11663 km/s
T(ϵ)≈2πrs3/2k +3πrs3/2ϵ2k 
T(ϵ)−T≤300
2π42828 (20425.9871−ϵ2 )3/2−88632≤300
ϵ≤0.047436
r0=rs
r′(ϵ)=−rs(1+ϵcos⁡(ϕ))−2cos⁡(ϕ)
r′(ϵ)=−rscos⁡(ϕ)(1+ϵcos⁡(ϕ))2 
r′(0)=−rscos⁡(ϕ))
r′′(ϵ)=2rscos2(ϕ)(1+ϵcos⁡(ϕ))−3
r′′(ϵ)=2rscos2(ϕ)
r(ϵ)≈rs−rsϵcos⁡(ϕ)+rsϵ2cos⁡2(ϕ)
2π(rs)3/2k +3π(rs)3/2ϵ2k ≤88932
3π(rs)3/2ϵ2k ≤300
ϵ≤0.0475
ϕ=2arctan⁡(1+ϵ1−ϵ tan⁡(ψ/2))
ϕ(0)=ψ
ϕ′(ϵ)=2[tan⁡(ψ/2)12 (1+ϵ1−ϵ )−1/2(1−ϵ−(1+ϵ)(−1)(1−ϵ)2 )1+(1+ϵ1−ϵ )tan2(ψ/2) ]
ϕ′′(ϵ)=2tan⁡(ψ/2)(1−ϵ)3/2(1+ϵ)1/2+(1−ϵ)1/2(1+ϵ)3/2tan2(ψ/2) 
ϕ′′(0)=(2sin⁡(ψ/2)cos⁡(ψ/2))(cos⁡2(ψ/2)+sin⁡2(ψ/2))=sin⁡ψ
ϕ=ψ+ϵsin⁡(ψ)+ϵ22 sin⁡(ψ)+0(ϵ3)
F0(t)=k2tℓs3 =ψ
F1(t)=sin⁡(ψ)=sin⁡(k2tℓs3 )
F2(t)=sin⁡(ψ)2 =sin⁡(k2tℓs3 )/2
ϕ(t,ϵ)=k2tℓs3 +ϵsin⁡(k2tℓs3 )+ϵ22 sin⁡(k2tℓs3 )
T(ϵ)=2πrs3/2k (1+32 ϵ2)
M=2πtT(ϵ) =2πt2πrs3/2k (1+32 ϵ2) =tk2ℓ3 (1+32 ϵ2)−1
letk2ℓ3 =a
ψ=M+ϵsin⁡(M)+ϵ22 sin⁡(2M)
ψ=ta(1−32 ϵ2)+ϵsin⁡(at(1−32 ϵ2))+ϵ22 sin⁡(2at(1−32 ϵ2))
ψ′(ϵ)=−3taϵ−3atϵ2cos⁡(at(1−32 ϵ2))+sin⁡(at(1−32 ϵ2))−3ϵ3atcos⁡(2at(1−32 ϵ2))+ϵsin⁡(at(1−32 ϵ2))
ψ′′(ϵ)=−3ta+sin⁡(2at)
ψ(ϵ)=ψ(0)+ϵψ′(0)+ϵ22 ψ′′(0)
ψ(ϵ)=tk2ℓ3 +ϵsin⁡(tk2ℓ3 )+ϵ2(−32 tk2ℓ3 +12 sin⁡(2tk2ℓ3 )
ϕ(t)=ψ+ϵsin⁡(ψ)+ϵ22 sin⁡(ψ)
f0(t)=ψ=tk2ℓ3 
ϕ(t)=tk2ℓ3 +ϵsin⁡(tk2ℓ3 )+ϵ22 sin⁡(tk2ℓ3 )
ϵ2


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I am a wiki mini-janitor. I clean up the messes YOU make.

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