Tin(IV) iodide

Tin(IV) iodide
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Template:Longitem	Template:Chem2
Molar mass	Template:Chem molar mass
Appearance	red-orange crystalline solid
Density	4.56 g/cm3
Melting point	Template:Chembox CalcTemperatures
Boiling point	Template:Chembox CalcTemperatures
Template:Longitem	2.106
Template:Longitem	Cubic, cP40
Template:Longitem	Pa-3 No. 205
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Tin(IV) iodide, also known as stannic iodide, is the chemical compound with the formula Template:Chem2. This tetrahedral molecule crystallizes as a bright orange solid that dissolves readily in nonpolar solvents such as benzene.^[1]

Preparation

The compound is usually prepared by the reaction of tin and iodine:^[2]

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Chemical properties

The compound hydrolyses in water.^[3] In hydroiodic acid, it reacts to form a rare example of a hexaiodometallate (here hexaiodostannate(IV)):^[2]

SnI₄ + 2 I⁻ → [SnI₆]²⁻

Physical properties

Tin(IV) iodide is an orange solid under standard conditions.^[3] It has a cubic crystal structure with the space group Pa3 (space group no. 205), the lattice parameter a = 1226 pm and eight formula units per unit cell.^[4] This corresponds approximately to a cubic close packing of iodine atoms in which 1/8 of all tetrahedral gaps are occupied by tin atoms. This leads to discrete tetrahedral SnI₄ molecules.^[5]