Talk:Poisson distribution

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Latest comment: 23 September 2024 by 89.23.239.207 in topic Add a simple introduction
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Adding a section on the CDF

Would it make sense to add a subsection for the CDF under the definitions, like there is for the Binomial distribution? FynnFreyer (talk) 19:07, 21 November 2023 (UTC)Reply

Modelled after the linked section it could look like this:
The cumulative distribution function can be expressed as:
F(k;λ)=Pr(Xk)=eλi=0kλii!,
where k is the "floor" under k, i.e. the greatest integer less than or equal to k, and ! is the factorial function.
It can also be represented in terms of the upper incomplete gamma function Γ or the regularized gamma function Q, as follows:
[1]
F(k;λ)=Γ(k+1,λk!=Q(k+1,λ).
FynnFreyer (talk) 19:24, 21 November 2023 (UTC)Reply

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Other Properties - Mitzenmacher

Source does not support this statement in the article:

and Pr(YE[Y])12.

See https://imgur.com/a/3lE0VDa

2A02:1811:351E:AF00:2966:4372:24C8:154B (talk) — Preceding undated comment added 23:58, 12 January 2024 (UTC)Reply

You are right: there is a typo in the source. However the statement on Wikipedia is correct:
Value of μ (Yμ)=k=0μeμμkk! Numerical approx.
1 2/e 0.73575...
2 5/e2 0.67667...
3 13/e3 0.64723...
4 0.62883...
5 0.61596...
More values can be obtained, e.g, with the following Python function
f = lambda n : sum(n**k * math.exp(-n) / math.factorial(k) for k in range(n + 1))
(note that this is poorly implemented, and that it overflows for μ ≥ 144).
In view of this, it's pretty clear that the mistake in the source is a typo rather than an actual mathematical error. Still, it's a problem... Especially since I wouldn't know where to find a source for this kind of statement. It's not too hard to see that the statement should be true for large μ (e.g, because the variables Yμ can be coupled in such a way that (Yμμ)μ is a random walk whose increments are centered and have variance 1), but even if someone provides a proof here, it might be considered original research.
As far as I'm concerned:
  • the fact that there is a mistake is not a huge problem, since it's clearly a typo; but I understand that some people might disagree;
  • the fact that there is no proof in the source is a bigger problem;
  • I think the statement is cool, but it's relevance is actually not so clear.
Malparti (talk) 18:57, 13 January 2024 (UTC)Reply

Add a simple introduction

This article is hard to read unless you already know what a Poisson distribution is, and that is unnecessary.

It would help to start out with a simple introduction of the term Poisson_process. Perhaps add an illustration to help the reader. Subsequently use this section to define the Poisson distribution. — Preceding unsigned comment added by 89.23.239.207 (talk) 13:28, 23 September 2024 (UTC)Reply

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