Talk:Graph homomorphism
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Definition issue
The definition is wrong. For example, in the condition
- δE = δE′ o fE
the range of the left side is sets of E-vertices, while the range of the right side is sets of E'-vertices.
I'm not correcting it right now because
- Wikipedia's being slow and flaky
- I don't have a reference for this concept.
Anyway, I suspect it could be stated a lot more simply, without so much formalism. Dbenbenn 21:42, 9 Jan 2005 (UTC)
- You are right the definition is wrong. I will fix it in the next few days. As for the simplicity: What I really meant to do is draw some commutative diagrams. The obscure equations are just placeholders until I have created the diagrams. MathMartin 13:03, 10 Jan 2005 (UTC)
It appears that the map from a graph to is not a graph homomorphism. I find that surprising; I think it should be mentioned explicitly. Dbenbenn 15:20, 10 Jan 2005 (UTC)
- You are correct again. I have to modify the functions to allow for the removal of edges and arrows by mapping them onto vertices. MathMartin 17:08, 10 Jan 2005 (UTC)
Now the definition should be correct, but I will still try to make it more clear. MathMartin 14:01, 12 Jan 2005 (UTC)
Simpler definition
The new definition looks correct, but scary! What do you think of the following simplification?
- A graph homomorphism from a graph to a graph maps vertices of to vertices of such that
- if is an edge of , then is an edge of , or , and
- if is a directed edge of , then is a directed edge of (in the same direction), or .
Basically, we don't really need to talk about the homomorphism's values on the edges, since that value is determined by the value on vertices. Dbenbenn 14:27, 12 Jan 2005 (UTC)
Your definition is simpler but only valid for homomorphisms between simple graphs. I understand your concerns, I do not like the definition either and I will try to make it clearer. Perhaps it would be best to include both definitions and point out the difference ? MathMartin 16:46, 12 Jan 2005 (UTC)
- Oh, right. The problem is that with either loops or multiedges, the definition of "monomorphism" gets broken. How about the following slightly less simple version:
- A graph homomorphism from a graph to a graph is a function on the edges and vertices of such that
- vertices of go to vertices of ,
- if is an edge of with endpoints and then either is an edge of with endpoints and , or , and
- if is a directed edge of from to then either is a directed edge of from to , or .
- By the way, the definition in the article is still slightly broken. Where does send a vertex in the range ? Dbenbenn 21:41, 12 Jan 2005 (UTC)
I extended your definition slightly to clarify the domain and codomain of f, because later we talk about bijection and it has to be clear where the f is defined. Otherwise I think your definition is easier to understand and the article is now in a useable state.MathMartin 10:19, 25 Jan 2005 (UTC)
WRONG DEFINITION
I do not agree with this definition at all: it might be a good definition for a graph contraction but not for graph homomorphism.
One of the fundamental property of graph homomorphism is that a graph G is k colorable iff G has a homomorphism to the complete graph on k vertices. This is the reason why the property to have a homomorphism to some fixed graph H is called 'H-colorability'. According to your definition, every graph has a homomorphism to .
Th standard definition of a homomorphism is the following: A homorphism from a graph G to a graph H is a mapping from the vertex set of G to the vertex set of H so that two adjacent vertices of G are mapped to two adjacent vertices of H. This definition can easily be extended to directed graphs and to graphs with loops (if v has a loop attached, v is adjacent to v thus f(v) is adjacent to f(v), that is: f(v) has a loop attached). Extension to multigraphs is not usual at all.
Reference:
P. Hell and J. Nesetril, Graphs and Homorphisms, Oxford Lecture Series in Mathematics and its Applications 28, Oxford University Press, 2004.
pom 11:25, 13 November 2005 (UTC)
I think that terms weak and strong homomorphism need to be introduced. Weak homomorphism does not take the directions of lines into account while strong does. A proper definition should introduce two functions, f1 and f1 where f1 maps vertices and f2 maps lines. If these two functions are bijections and there is a (strong, weak) homomorphism, we have a (strong, weak) graph isomorphism. --212.235.208.165 (talk) 10:41, 24 November 2008 (UTC)