Algebraic number: Difference between revisions

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{{Short description|Complex number that is a root of a non-zero polynomial in one variable with rational coefficients}}
{{Short description|Type of complex number}}
{{Distinguish|Algebraic solution}}
{{Distinguish|Algebraic solution}}
{{Use shortened footnotes|date=September 2024}}
{{Use shortened footnotes|date=September 2024}}
[[File:Isosceles right triangle with legs length 1.svg|thumb|200px|The square root of 2 is an algebraic number equal to the length of the [[hypotenuse]] of a [[right triangle]] with legs of length 1.]]
[[File:Isosceles right triangle with legs length 1.svg|thumb|200px|The square root of 2 is an algebraic number equal to the length of the [[hypotenuse]] of a [[right triangle]] with legs of length 1.]]


In [[mathematics]], an '''algebraic number''' is a number that is a [[root of a function|root]] of a non-zero [[polynomial]] in one variable with [[integer]] (or, equivalently, [[Rational number|rational]]) coefficients.  For example, the [[golden ratio]] <math>(1 + \sqrt{5})/2</math> is an algebraic number, because it is a root of the polynomial <math>X^2 - X - 1</math>, i.e., a solution of the equation <math>x^2 - x - 1 = 0</math>, and the [[complex number]] <math>1 + i</math> is algebraic as a root of <math>X^4 + 4</math>. Algebraic numbers include all [[integer]]s, [[rational number]]s, and [[nth root|''n''-th roots of integers]].
In [[mathematics]], an '''algebraic number''' is a number that is a [[root of a function|root]] of a non-zero [[polynomial]] in one variable with [[integer]] (or, equivalently, [[Rational number|rational]]) coefficients.  For example, the [[golden ratio]] <math>(1 + \sqrt{5})/2</math> is an algebraic number, because it is a root of the polynomial <math>x^2 - x - 1</math>, i.e., a solution to the equation <math>x^2 - x - 1 = 0</math>, and the [[complex number]] <math>1 + i</math> is algebraic because it is a root of the polynomial <math>x^4 + 4</math>. Algebraic numbers include all [[integer]]s, [[rational number]]s, and [[nth root|''n''-th roots of integers]].


Algebraic [[complex number]]s are closed under addition, subtraction, multiplication and division, and hence form a [[field (mathematics)|field]], denoted <math>\overline{\Q}</math>. The set of algebraic [[real number]]s <math>\overline{\Q} \cap \R</math> is also a field.
Algebraic [[complex number]]s are closed under addition, subtraction, multiplication and division, and hence form a [[field (mathematics)|field]], denoted <math>\overline{\Q}</math>. The set of algebraic [[real number]]s <math>\overline{\Q} \cap \R</math> is also a field.


Numbers which are not algebraic are called [[transcendental number|transcendental]] and include [[pi|{{pi}}]] and {{mvar|[[e (mathematical constant)|e]]}}. There are [[countable set|countably many]] algebraic numbers, hence [[almost all]] real (or complex) numbers (in the sense of [[Lebesgue measure]]) are transcendental.
Numbers which are not algebraic are called [[transcendental number|transcendental]] and include [[pi|{{pi}}]] and {{mvar|[[e (mathematical constant)|e]]}}. There are [[countable set|countably infinite]] algebraic numbers, hence [[almost all]] real (or complex) numbers (in the sense of [[Lebesgue measure]]) are transcendental.


==Examples==
==Examples==
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===Degree of simple extensions of the rationals as a criterion to algebraicity===
===Degree of simple extensions of the rationals as a criterion to algebraicity===
For any {{math|&alpha;}}, the [[simple extension]] of the rationals by {{math|&alpha;}}, denoted by <math>\Q(\alpha)</math> (whose elements are the <math>f(\alpha)</math> for <math>f</math> a [[rational function]] with rational coefficients which is defined at <math>\alpha</math>), is of finite [[Degree of a field extension|degree]] if and only if {{math|&alpha;}} is an algebraic number.
For any {{tmath|\alpha}}, the [[simple extension]] of the rationals by {{tmath|\alpha}}, denoted by <math>\Q(\alpha)</math> (whose elements are the <math>f(\alpha)</math> for <math>f</math> a [[rational function]] with rational coefficients which is defined at <math>\alpha</math>), is of finite [[Degree of a field extension|degree]] if and only if {{tmath|\alpha}} is an algebraic number.


The condition of finite degree means that there is a finite set <math>\{a_i | 1\le i\le k\}</math> in <math>\Q(\alpha)</math> such that <math>\Q(\alpha) = \sum_{i=1}^k a_i \Q</math>; that is, every member in <math>\Q(\alpha)</math> can be written as <math>\sum_{i=1}^k a_i q_i</math> for some rational numbers <math>\{q_i | 1\le i\le k\}</math> (note that the set <math>\{a_i\}</math> is fixed).
The condition of finite degree means that there is a fixed set of numbers <math>\{a_i\}</math> of finite [[cardinality]] {{tmath|k}} with elements in <math>\Q(\alpha)</math> such that <math>\textstyle \Q(\alpha) = \sum_{i=1}^k a_i \Q</math>; that is, each element of <math>\Q(\alpha)</math> can be written as a sum <math>\textstyle \sum_{i=1}^k a_i q_i</math> for some rational coefficients <math>\{q_i \}</math>.


Indeed, since the <math>a_i-s</math> are themselves members of <math>\Q(\alpha)</math>, each can be expressed as sums of products of rational numbers and powers of {{math|&alpha;}}, and therefore this condition is equivalent to the requirement that for some finite <math>n</math>, <math>\Q(\alpha) = \{\sum_{i=-n}^n \alpha^{i} q_i | q_i\in \Q\}</math>.
Since the <math>a_i</math> are themselves members of <math>\Q(\alpha)</math>, each can be expressed as sums of products of rational numbers and powers of {{tmath|\alpha}}, and therefore this condition is equivalent to the requirement that for some finite <math>n</math>, <math display=block>\Q(\alpha) = \biggl\lbrace \sum_{i=-n}^n \alpha^{i} q_i \mathbin{\bigg|} q_i\in \Q\biggr\rbrace.</math>


The latter condition is equivalent to <math>\alpha^{n+1}</math>, itself a member of <math>\Q(\alpha)</math>, being expressible as <math>\sum_{i=-n}^n \alpha^i q_i</math> for some rationals <math>\{q_i\}</math>, so <math>\alpha^{2n+1} = \sum_{i=0}^{2n} \alpha^i q_{i-n}</math> or, equivalently, {{math|&alpha;}} is a root of <math>x^{2n+1}-\sum_{i=0}^{2n} x^i q_{i-n}</math>; that is, an algebraic number with a minimal polynomial of degree not larger than <math>2n+1</math>.
The latter condition is equivalent to <math>\alpha^{n+1}</math>, itself a member of <math>\Q(\alpha)</math>, being expressible as <math>\textstyle \sum_{i=-n}^n \alpha^i q_i</math> for some rationals <math>\{q_i\}</math>, so <math>\textstyle \alpha^{2n+1} = \sum_{i=0}^{2n} \alpha^i q_{i-n}</math> or, equivalently, {{tmath|\alpha}} is a root of <math>\textstyle x^{2n+1}-\sum_{i=0}^{2n} x^i q_{i-n}</math>; that is, an algebraic number with a minimal polynomial of degree not larger than <math>2n+1</math>.


It can similarly be proven that for any finite set of algebraic numbers <math>\alpha_1</math>, <math>\alpha_2</math>... <math>\alpha_n</math>, the field extension <math>\Q(\alpha_1, \alpha_2, ... \alpha_n)</math> has a finite degree.
It can similarly be proven that for any finite set of algebraic numbers <math>\alpha_1</math>, <math>\alpha_2</math>... <math>\alpha_n</math>, the field extension <math>\Q(\alpha_1, \alpha_2, ... \alpha_n)</math> has a finite degree.
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The sum, difference, product, and quotient (if the denominator is nonzero) of two algebraic numbers is again algebraic:
The sum, difference, product, and quotient (if the denominator is nonzero) of two algebraic numbers is again algebraic:


For any two algebraic numbers {{math|&alpha;}}, {{math|&beta;}}, this follows directly from the fact that the [[simple extension]] <math>\Q(\gamma)</math>, for <math>\gamma</math> being either <math>\alpha+\beta</math>, <math>\alpha-\beta</math>, <math>\alpha\beta</math> or (for <math>\beta\ne 0</math>) <math>\alpha/\beta</math>, is a [[linear subspace]] of the finite-[[Degree of a field extension|degree]] field extension <math>\Q(\alpha,\beta)</math>, and therefore has a finite degree itself, from which it follows (as shown [[#Degree of simple extensions of the rationals as a criterion to algebraicity|above]]) that <math>\gamma</math> is algebraic.
For any two algebraic numbers {{tmath|\alpha}}, {{tmath|\beta}}, this follows directly from the fact that the [[simple extension]] <math>\Q(\gamma)</math>, for <math>\gamma</math> being either <math>\alpha+\beta</math>, <math>\alpha-\beta</math>, <math>\alpha\beta</math> or (for <math>\beta\ne 0</math>) <math>\alpha/\beta</math>, is a [[linear subspace]] of the finite-[[Degree of a field extension|degree]] field extension <math>\Q(\alpha,\beta)</math>, and therefore has a finite degree itself, from which it follows (as shown [[#Degree of simple extensions of the rationals as a criterion to algebraicity|above]]) that <math>\gamma</math> is algebraic.


An alternative way of showing this is constructively, by using the [[resultant]].
An alternative way of showing this is constructively, by using the [[resultant]].
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Every root of a polynomial equation whose coefficients are ''algebraic numbers'' is again algebraic. That can be rephrased by saying that the field of algebraic numbers is [[algebraically closed field|algebraically closed]]. In fact, it is the smallest algebraically closed field containing the rationals and so it is called the [[algebraic closure]] of the rationals.
Every root of a polynomial equation whose coefficients are ''algebraic numbers'' is again algebraic. That can be rephrased by saying that the field of algebraic numbers is [[algebraically closed field|algebraically closed]]. In fact, it is the smallest algebraically closed field containing the rationals and so it is called the [[algebraic closure]] of the rationals.


That the field of algebraic numbers is algebraically closed can be proven as follows: Let {{math|&beta;}} be a root of a polynomial <math> \alpha_0 + \alpha_1 x + \alpha_2 x^2 ... +\alpha_n x^n</math> with coefficients that are algebraic numbers <math>\alpha_0</math>, <math>\alpha_1</math>, <math>\alpha_2</math>... <math>\alpha_n</math>. The field extension <math>\Q^\prime \equiv \Q(\alpha_1, \alpha_2, ... \alpha_n)</math> then has a finite degree with respect to <math>\Q</math>. The simple extension <math>\Q^\prime(\beta)</math> then has a finite degree with respect to <math>\Q^\prime</math> (since all powers of {{math|&beta;}} can be expressed by powers of up to <math>\beta^{n-1}</math>). Therefore, <math>\Q^\prime(\beta) = \Q(\beta, \alpha_1, \alpha_2, ... \alpha_n)</math> also has a finite degree with respect to <math>\Q</math>. Since <math>\Q(\beta)</math> is a linear subspace of <math>\Q^\prime(\beta)</math>, it must also have a finite degree with respect to <math>\Q</math>, so {{math|&beta;}} must be an algebraic number.
That the field of algebraic numbers is algebraically closed can be proven as follows: Let {{tmath|\beta}} be a root of a polynomial <math> \alpha_0 + \alpha_1 x + \alpha_2 x^2 ... +\alpha_n x^n</math> with coefficients that are algebraic numbers <math>\alpha_0</math>, <math>\alpha_1</math>, <math>\alpha_2</math>... <math>\alpha_n</math>. The field extension <math>\Q^\prime \equiv \Q(\alpha_1, \alpha_2, ... \alpha_n)</math> then has a finite degree with respect to <math>\Q</math>. The simple extension <math>\Q^\prime(\beta)</math> then has a finite degree with respect to <math>\Q^\prime</math> (since all powers of {{tmath|\beta}} can be expressed by powers of up to <math>\beta^{n-1}</math>). Therefore, <math>\Q^\prime(\beta) = \Q(\beta, \alpha_1, \alpha_2, ... \alpha_n)</math> also has a finite degree with respect to <math>\Q</math>. Since <math>\Q(\beta)</math> is a linear subspace of <math>\Q^\prime(\beta)</math>, it must also have a finite degree with respect to <math>\Q</math>, so {{tmath|\beta}} must be an algebraic number.


==Related fields==
==Related fields==

Latest revision as of 06:35, 2 November 2025

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File:Isosceles right triangle with legs length 1.svg
The square root of 2 is an algebraic number equal to the length of the hypotenuse of a right triangle with legs of length 1.

In mathematics, an algebraic number is a number that is a root of a non-zero polynomial in one variable with integer (or, equivalently, rational) coefficients. For example, the golden ratio (1+5)/2 is an algebraic number, because it is a root of the polynomial x2x1, i.e., a solution to the equation x2x1=0, and the complex number 1+i is algebraic because it is a root of the polynomial x4+4. Algebraic numbers include all integers, rational numbers, and n-th roots of integers.

Algebraic complex numbers are closed under addition, subtraction, multiplication and division, and hence form a field, denoted . The set of algebraic real numbers is also a field.

Numbers which are not algebraic are called transcendental and include [[pi|Template:Pi]] and Template:Mvar. There are countably infinite algebraic numbers, hence almost all real (or complex) numbers (in the sense of Lebesgue measure) are transcendental.

Examples

Properties

File:Algebraicszoom.png
Algebraic numbers on the complex plane colored by degree (bright orange/red = 1, green = 2, blue = 3, yellow = 4). The larger points come from polynomials with smaller integer coefficients.

Degree of simple extensions of the rationals as a criterion to algebraicity

For any Template:Tmath, the simple extension of the rationals by Template:Tmath, denoted by (α) (whose elements are the f(α) for f a rational function with rational coefficients which is defined at α), is of finite degree if and only if Template:Tmath is an algebraic number.

The condition of finite degree means that there is a fixed set of numbers {ai} of finite cardinality Template:Tmath with elements in (α) such that (α)=i=1kai; that is, each element of (α) can be written as a sum i=1kaiqi for some rational coefficients {qi}.

Since the ai are themselves members of (α), each can be expressed as sums of products of rational numbers and powers of Template:Tmath, and therefore this condition is equivalent to the requirement that for some finite n, (α)={i=nnαiqi|qi}.

The latter condition is equivalent to αn+1, itself a member of (α), being expressible as i=nnαiqi for some rationals {qi}, so α2n+1=i=02nαiqin or, equivalently, Template:Tmath is a root of x2n+1i=02nxiqin; that is, an algebraic number with a minimal polynomial of degree not larger than 2n+1.

It can similarly be proven that for any finite set of algebraic numbers α1, α2... αn, the field extension (α1,α2,...αn) has a finite degree.

Field

File:Algebraic number in the complex plane.png
Algebraic numbers colored by degree (blue = 4, cyan = 3, red = 2, green = 1). The unit circle is black.Template:Explain

The sum, difference, product, and quotient (if the denominator is nonzero) of two algebraic numbers is again algebraic:

For any two algebraic numbers Template:Tmath, Template:Tmath, this follows directly from the fact that the simple extension (γ), for γ being either α+β, αβ, αβ or (for β0) α/β, is a linear subspace of the finite-degree field extension (α,β), and therefore has a finite degree itself, from which it follows (as shown above) that γ is algebraic.

An alternative way of showing this is constructively, by using the resultant.

Algebraic numbers thus form a fieldTemplate:Sfn (sometimes denoted by 𝔸, but that usually denotes the adele ring).

Algebraic closure

Every root of a polynomial equation whose coefficients are algebraic numbers is again algebraic. That can be rephrased by saying that the field of algebraic numbers is algebraically closed. In fact, it is the smallest algebraically closed field containing the rationals and so it is called the algebraic closure of the rationals.

That the field of algebraic numbers is algebraically closed can be proven as follows: Let Template:Tmath be a root of a polynomial α0+α1x+α2x2...+αnxn with coefficients that are algebraic numbers α0, α1, α2... αn. The field extension (α1,α2,...αn) then has a finite degree with respect to . The simple extension (β) then has a finite degree with respect to (since all powers of Template:Tmath can be expressed by powers of up to βn1). Therefore, (β)=(β,α1,α2,...αn) also has a finite degree with respect to . Since (β) is a linear subspace of (β), it must also have a finite degree with respect to , so Template:Tmath must be an algebraic number.

Related fields

Numbers defined by radicals

Any number that can be obtained from the integers using a finite number of additions, subtractions, multiplications, divisions, and taking (possibly complex) Template:Mvarth roots where Template:Mvar is a positive integer are algebraic. The converse, however, is not true: there are algebraic numbers that cannot be obtained in this manner. These numbers are roots of polynomials of degree 5 or higher, a result of Galois theory (see Quintic equations and the Abel–Ruffini theorem). For example, the equation:

x5x1=0

has a unique real root, ≈ 1.1673, that cannot be expressed in terms of only radicals and arithmetic operations.

Closed-form number

Script error: No such module "Labelled list hatnote". Algebraic numbers are all numbers that can be defined explicitly or implicitly in terms of polynomials, starting from the rational numbers. One may generalize this to "closed-form numbers", which may be defined in various ways. Most broadly, all numbers that can be defined explicitly or implicitly in terms of polynomials, exponentials, and logarithms are called "elementary numbers", and these include the algebraic numbers, plus some transcendental numbers. Most narrowly, one may consider numbers explicitly defined in terms of polynomials, exponentials, and logarithms – this does not include all algebraic numbers, but does include some simple transcendental numbers such as Template:Mvar or ln 2.

Algebraic integers

File:Leadingcoeff.png
Visualisation of the (countable) field of algebraic numbers in the complex plane. Colours indicate the leading integer coefficient of the polynomial the number is a root of (red = 1 i.e. the algebraic integers, green = 2, blue = 3, yellow = 4...). Points becomes smaller as the other coefficients and number of terms in the polynomial become larger. View shows integers 0,1 and 2 at bottom right, +i near top.

Script error: No such module "Labelled list hatnote". An algebraic integer is an algebraic number that is a root of a polynomial with integer coefficients with leading coefficient 1 (a monic polynomial). Examples of algebraic integers are 5+132, 26i, and 12(1+i3). Therefore, the algebraic integers constitute a proper superset of the integers, as the latter are the roots of monic polynomials Template:Math for all k. In this sense, algebraic integers are to algebraic numbers what integers are to rational numbers.

The sum, difference and product of algebraic integers are again algebraic integers, which means that the algebraic integers form a ring. The name algebraic integer comes from the fact that the only rational numbers that are algebraic integers are the integers, and because the algebraic integers in any number field are in many ways analogous to the integers. If Template:Math is a number field, its ring of integers is the subring of algebraic integers in Template:Math, and is frequently denoted as Template:Math. These are the prototypical examples of Dedekind domains.

Special classes

Notes

Template:Reflist

References

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Template:Algebraic numbers Template:Number systems Template:Authority control

  1. Some of the following examples come from Template:Harvtxt
  2. Also, Liouville's theorem can be used to "produce as many examples of transcendental numbers as we please," cf. Template:Harvtxt