Fibonacci sequence: Difference between revisions

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Closed-form expression: Eliminate equation that repeats a recently provided equation
 
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{{Short description|Numbers obtained by adding the two previous ones}}
{{Short description|Numbers obtained by adding the two previous ones}}
{{For|the chamber ensemble|Fibonacci Sequence (ensemble)}}
{{For|the chamber ensemble|Fibonacci Sequence (ensemble)}}
{{pp-pc}}


In mathematics, the '''Fibonacci sequence''' is a [[Integer sequence|sequence]] in which each element is the sum of the two elements that precede it. Numbers that are part of the Fibonacci sequence are known as '''Fibonacci numbers''', commonly denoted {{nowrap|{{math|''F<sub>n</sub>''}}{{space|hair}}}}. Many writers begin the sequence with 0 and 1, although some authors start it from 1 and 1<ref>Richard A. Brualdi, ''Introductory Combinatorics'', Fifth edition, Pearson, 2005</ref><ref>Peter Cameron, ''Combinatorics: Topics, Techniques, Algorithms'', Cambridge University Press, 1994</ref> and some (as did Fibonacci) from 1 and 2. Starting from 0 and 1, the sequence begins
In mathematics, the '''Fibonacci sequence''' is a [[Integer sequence|sequence]] in which each element is the sum of the two elements that precede it. Numbers that are part of the Fibonacci sequence are known as '''Fibonacci numbers''', commonly denoted {{nowrap|{{math|''F<sub>n</sub>''}}{{space|hair}}}}. Many writers begin the sequence with 0 and 1, although some authors start it from 1 and 1<ref>Richard A. Brualdi, ''Introductory Combinatorics'', Fifth edition, Pearson, 2005</ref><ref>Peter Cameron, ''Combinatorics: Topics, Techniques, Algorithms'', Cambridge University Press, 1994</ref> and some (as did [[Fibonacci]]) from 1 and 2. Starting from 0 and 1, the sequence begins
: 0, 1, 1, 2, 3, 5, 8, 13, 21, 34, 55, 89, 144, ... {{OEIS|A000045}}
: 0, 1, 1, 2, 3, 5, 8, 13, 21, 34, 55, 89, 144, ... {{OEIS|A000045}}


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| 4181
| 4181
|}
|}
The Fibonacci sequence can be extended to negative integer indices by following the same recurrence relation in the negative direction {{OEIS|A039834}}: {{tmath|1= F_1=1}}, {{tmath|1= F_0= 0}}, and {{tmath|1= F_{n}=F_{n+2} - F_{n+1} }} for {{math|''n'' < 0 }}. Nearly all properties of Fibonacci numbers do not depend upon whether the indices are positive or negative. The values for positive and negative indices obey the relation:<ref>{{cite book
| last = Vajda | first = Steven | author-link = Steven Vajda
| year = 1989
| title = Fibonacci & Lucas Numbers, and the Golden Section: Theory and Applications
| place = Chichester | publisher = Ellis Horwood
| isbn = 0-7458-0715-1
| page = 10
}}</ref>
<math display=block> F_{-n} = (-1)^{n+1} F_n. </math>


== History ==
== History ==
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The Fibonacci sequence appears in [[Indian mathematics]], in connection with [[Sanskrit prosody]].<ref name="HistoriaMathematica">{{Citation|first=Parmanand|last=Singh|title= The So-called Fibonacci numbers in ancient and medieval India|journal=Historia Mathematica|volume=12|issue=3|pages=229–244|year=1985|doi = 10.1016/0315-0860(85)90021-7|doi-access=free}}</ref><ref name="knuth-v1">{{Citation|title=The Art of Computer Programming|volume=1|first=Donald|last=Knuth| author-link =Donald Knuth |publisher=Addison Wesley|year=1968|isbn=978-81-7758-754-8|url=https://books.google.com/books?id=MooMkK6ERuYC&pg=PA100|page=100|quote=Before Fibonacci wrote his work, the sequence Fn had already been discussed by Indian scholars, who had long been interested in rhythmic patterns&nbsp;... both Gopala (before 1135&nbsp;AD) and Hemachandra (c.&nbsp;1150) mentioned the numbers 1,2,3,5,8,13,21 explicitly [see P. Singh Historia Math 12 (1985) 229–44]" p. 100 (3d ed)&nbsp;...}}</ref>{{sfn|Livio|2003|p=197}} In the Sanskrit poetic tradition, there was interest in enumerating all patterns of long (L) syllables of 2 units duration, juxtaposed with short (S) syllables of 1 unit duration. Counting the different patterns of successive L and S with a given total duration results in the Fibonacci numbers: the number of patterns of duration {{mvar|m}} units is {{math|''F''<sub>''m''+1</sub>}}.<ref name="Donald Knuth 2006 50">{{Citation|title = The Art of Computer Programming | volume = 4. Generating All Trees – History of Combinatorial Generation | first = Donald | last = Knuth | author-link = Donald Knuth |publisher= Addison–Wesley |year= 2006 | isbn= 978-0-321-33570-8 | page = 50 | url= https://books.google.com/books?id=56LNfE2QGtYC&q=rhythms&pg=PA50 | quote = it was natural to consider the set of all sequences of [L] and [S] that have exactly m beats.  ... there are exactly Fm+1 of them.  For example the 21 sequences when {{math|1=''m'' = 7}} are: [gives list].  In this way Indian prosodists were led to discover the Fibonacci sequence, as we have observed in Section 1.2.8 (from v.1)}}</ref>
The Fibonacci sequence appears in [[Indian mathematics]], in connection with [[Sanskrit prosody]].<ref name="HistoriaMathematica">{{Citation|first=Parmanand|last=Singh|title= The So-called Fibonacci numbers in ancient and medieval India|journal=Historia Mathematica|volume=12|issue=3|pages=229–244|year=1985|doi = 10.1016/0315-0860(85)90021-7|doi-access=free}}</ref><ref name="knuth-v1">{{Citation|title=The Art of Computer Programming|volume=1|first=Donald|last=Knuth| author-link =Donald Knuth |publisher=Addison Wesley|year=1968|isbn=978-81-7758-754-8|url=https://books.google.com/books?id=MooMkK6ERuYC&pg=PA100|page=100|quote=Before Fibonacci wrote his work, the sequence Fn had already been discussed by Indian scholars, who had long been interested in rhythmic patterns&nbsp;... both Gopala (before 1135&nbsp;AD) and Hemachandra (c.&nbsp;1150) mentioned the numbers 1,2,3,5,8,13,21 explicitly [see P. Singh Historia Math 12 (1985) 229–44]" p. 100 (3d ed)&nbsp;...}}</ref>{{sfn|Livio|2003|p=197}} In the Sanskrit poetic tradition, there was interest in enumerating all patterns of long (L) syllables of 2 units duration, juxtaposed with short (S) syllables of 1 unit duration. Counting the different patterns of successive L and S with a given total duration results in the Fibonacci numbers: the number of patterns of duration {{mvar|m}} units is {{math|''F''<sub>''m''+1</sub>}}.<ref name="Donald Knuth 2006 50">{{Citation|title = The Art of Computer Programming | volume = 4. Generating All Trees – History of Combinatorial Generation | first = Donald | last = Knuth | author-link = Donald Knuth |publisher= Addison–Wesley |year= 2006 | isbn= 978-0-321-33570-8 | page = 50 | url= https://books.google.com/books?id=56LNfE2QGtYC&q=rhythms&pg=PA50 | quote = it was natural to consider the set of all sequences of [L] and [S] that have exactly m beats.  ... there are exactly Fm+1 of them.  For example the 21 sequences when {{math|1=''m'' = 7}} are: [gives list].  In this way Indian prosodists were led to discover the Fibonacci sequence, as we have observed in Section 1.2.8 (from v.1)}}</ref>


Knowledge of the Fibonacci sequence was expressed as early as [[Pingala]] ({{circa}}&nbsp;450&nbsp;BC–200&nbsp;BC). Singh cites Pingala's cryptic formula ''misrau cha'' ("the two are mixed") and scholars who interpret it in context as saying that the number of patterns for {{mvar|m}} beats ({{math|''F''<sub>''m''+1</sub>}}) is obtained by adding one [S] to the {{math|''F''<sub>''m''</sub>}} cases and one [L] to the {{math|''F''<sub>''m''−1</sub>}} cases.<ref>{{Citation | last = Agrawala | first = VS | year = 1969 | title = ''Pāṇinikālīna Bhāratavarṣa'' (Hn.). Varanasi-I: TheChowkhamba Vidyabhawan | quote = SadgurushiShya writes that Pingala was a younger brother of Pāṇini [Agrawala 1969, lb]. There is an alternative opinion that he was a maternal uncle of Pāṇini [Vinayasagar 1965, Preface, 121]. ... Agrawala  [1969,  463–76],  after a careful investigation, in which he considered the views of earlier scholars, has concluded that Pāṇini lived between 480 and 410 BC}}</ref> [[Bharata Muni]] also expresses knowledge of the sequence in the ''[[Natya Shastra]]'' (c.&nbsp;100&nbsp;BC–c.&nbsp;350&nbsp;AD).<ref name=GlobalScience>{{Citation|title=Toward a Global Science|first=Susantha|last=Goonatilake|author-link=Susantha Goonatilake|publisher=Indiana University Press|year=1998|page=126|isbn=978-0-253-33388-9|url=https://books.google.com/books?id=SI5ip95BbgEC&pg=PA126}}</ref><ref name="HistoriaMathematica"/>
Knowledge of the Fibonacci sequence was expressed as early as [[Pingala]] ({{circa}}&nbsp;450&nbsp;BC–200&nbsp;BC). Singh cites Pingala's cryptic formula ''misrau cha'' ("the two are mixed") and scholars who interpret it in context as saying that the number of patterns for {{mvar|m}} beats ({{math|''F''<sub>''m''+1</sub>}}) is obtained by adding one [S] to the {{math|''F''<sub>''m''</sub>}} cases and one [L] to the {{math|''F''<sub>''m''−1</sub>}} cases.<ref>{{Citation | last = Agrawala | first = VS | year = 1969 | title = ''Pāṇinikālīna Bhāratavarṣa'' (Hn.). Varanasi-I: TheChowkhamba Vidyabhawan | quote = SadgurushiShya writes that Pingala was a younger brother of Pāṇini [Agrawala 1969, lb]. There is an alternative opinion that he was a maternal uncle of Pāṇini [Vinayasagar 1965, Preface, 121]. ... Agrawala  [1969,  463–76],  after a careful investigation, in which he considered the views of earlier scholars, has concluded that Pāṇini lived between 480 and 410 BC}}</ref> [[Bharata Muni]] also expresses knowledge of the sequence in the ''[[Natya Shastra]]'' ({{Circa}}&nbsp;100&nbsp;BC–{{Circa}}&nbsp;350&nbsp;AD).<ref name=GlobalScience>{{Citation|title=Toward a Global Science|first=Susantha|last=Goonatilake|author-link=Susantha Goonatilake|publisher=Indiana University Press|year=1998|page=126|isbn=978-0-253-33388-9|url=https://books.google.com/books?id=SI5ip95BbgEC&pg=PA126}}</ref><ref name="HistoriaMathematica"/>
However, the clearest exposition of the sequence arises in the work of [[Virahanka]] (c.&nbsp;700&nbsp;AD), whose own work is lost, but is available in a quotation by Gopala (c.&nbsp;1135):{{sfn|Livio|2003|p=197}}
However, the clearest exposition of the sequence arises in the work of [[Virahanka]] ({{Circa}}&nbsp;700&nbsp;AD), whose own work is lost, but is available in a quotation by Gopala ({{Circa}}&nbsp;1135):{{sfn|Livio|2003|p=197}}


<blockquote>Variations of two earlier meters [is the variation]&nbsp;...  For example, for [a meter of length] four, variations of meters of two [and] three being mixed, five happens. [works out examples 8, 13, 21]&nbsp;... In this way, the process should be followed in all ''mātrā-vṛttas'' [prosodic combinations].{{efn|"For four, variations of meters of two [and] three being mixed, five happens. For five, variations of two earlier—three [and] four, being mixed, eight is obtained. In this way, for six, [variations] of four [and] of five being mixed, thirteen happens. And like that, variations of two earlier meters being mixed, seven [[Mora (linguistics)|morae]] [is] twenty-one. In this way, the process should be followed in all mātrā-vṛttas" <ref>{{Citation|last=Velankar|first=HD|year=1962|title='Vṛttajātisamuccaya' of kavi Virahanka|publisher=Rajasthan Oriental Research Institute|location=Jodhpur|page=101}}</ref>}}</blockquote>
<blockquote>Variations of two earlier meters [is the variation]&nbsp;...  For example, for [a meter of length] four, variations of meters of two [and] three being mixed, five happens. [works out examples 8, 13, 21]&nbsp;... In this way, the process should be followed in all ''mātrā-vṛttas'' [prosodic combinations].{{efn|"For four, variations of meters of two [and] three being mixed, five happens. For five, variations of two earlier—three [and] four, being mixed, eight is obtained. In this way, for six, [variations] of four [and] of five being mixed, thirteen happens. And like that, variations of two earlier meters being mixed, seven [[Mora (linguistics)|morae]] [is] twenty-one. In this way, the process should be followed in all mātrā-vṛttas" <ref>{{Citation|last=Velankar|first=HD|year=1962|title='Vṛttajātisamuccaya' of kavi Virahanka|publisher=Rajasthan Oriental Research Institute|location=Jodhpur|page=101}}</ref>}}</blockquote>


[[Hemachandra]] (c.&nbsp;1150) is credited with knowledge of the sequence as well,<ref name=GlobalScience/> writing that "the sum of the last and the one before the last is the number&nbsp;... of the next mātrā-vṛtta."{{sfn|Livio|2003|p=197–198}}<ref>{{citation|last1=Shah|first1=Jayant|year=1991|title=A History of Piṅgala's Combinatorics|url=https://web.northeastern.edu/shah/papers/Pingala.pdf|publisher=[[Northeastern University]]|page=41|access-date=2019-01-04}}</ref>
[[Hemachandra]] ({{Circa}}&nbsp;1150) is credited with knowledge of the sequence as well,<ref name=GlobalScience/> writing that "the sum of the last and the one before the last is the number&nbsp;... of the next mātrā-vṛtta."{{sfn|Livio|2003|p=197–198}}<ref>{{citation|last1=Shah|first1=Jayant|year=1991|title=A History of Piṅgala's Combinatorics|url=https://web.northeastern.edu/shah/papers/Pingala.pdf|publisher=[[Northeastern University]]|page=41|access-date=2019-01-04}}</ref>


===Europe===
===Europe===
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== Relation to the golden ratio ==
== Relation to the golden ratio ==
{{main|Golden ratio}}
{{also|Golden ratio|Golden field}}


===Closed-form expression <span class="anchor" id="Binet's formula"></span>===
===Closed-form expression <span class="anchor" id="Binet's formula"></span>===
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</math>
</math>


where
where {{tmath|\varphi}} is the [[golden ratio]] and {{tmath|\psi}} is its [[Conjugate (square roots)|conjugate]],{{Sfn | Ball | 2003 | p = 156}}


<math display=block>
<math display=block>\begin{align}
\varphi = \frac{1 + \sqrt{5}}{2} \approx 1.61803\,39887\ldots
\varphi &= \tfrac12\bigl(1 + \sqrt{5}~\!\bigr)= \phantom{-}1.61803\ldots, \\[5mu]
</math>
\psi &= \tfrac12\bigl(1 - \sqrt{5}~\!\bigr) = -0.61803\ldots.
\end{align}</math>
The numbers {{tmath|\varphi}} and {{tmath|\psi}} are the two solutions of the [[quadratic equation]] {{tmath|1=\textstyle x^2 - x - 1 = 0}}, that is, {{tmath|1= (x - \varphi)(x - \psi) = x^2 - x - 1}}, and thus they satisfy the identities {{tmath|1= \varphi + \psi = 1}} and {{tmath|1= \varphi\psi = -1}}.


is the [[golden ratio]], and <math>\psi</math> is its [[Conjugate (square roots)|conjugate]]:{{Sfn | Ball | 2003 | p = 156}}
Since <math>\psi = -\varphi^{-1}</math>, Binet's formula can also be written as
 
<math display=block>
\psi = \frac{1 - \sqrt{5}}{2} = 1 - \varphi = - {1 \over \varphi} \approx -0.61803\,39887\ldots.
</math>
 
Since <math>\psi = -\varphi^{-1}</math>, this formula can also be written as


<math display=block>
<math display=block>
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</math>
</math>


To see the relation between the sequence and these constants,{{Sfn | Ball | 2003 | pp = 155–156}} note that <math>\varphi</math> and <math>\psi</math> are both solutions of the equation <math display=inline>x^2 = x + 1</math> and thus <math>x^n = x^{n-1} + x^{n-2},</math> so the powers of <math>\varphi</math> and <math>\psi</math> satisfy the Fibonacci recursion. In other words,
To see the relation between the sequence and these constants,{{Sfn | Ball | 2003 | pp = 155–156}} note that <math>\varphi</math> and <math>\psi</math> are also roots of <math>x^n = x^{n-1} + x^{n-2},</math> so the powers of <math>\varphi</math> and <math>\psi</math> satisfy the Fibonacci recurrence. In other words,


<math display=block>\begin{align}
<math display=block>\begin{align}
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<math display=block>U_n=a \varphi^n + b \psi^n</math>
<math display=block>U_n=a \varphi^n + b \psi^n</math>


satisfies the same recurrence,
satisfies the same recurrence. If {{mvar|a}} and {{mvar|b}} are chosen so that {{math|1=''U''<sub>0</sub> = 0}} and {{math|1=''U''<sub>1</sub> = 1}} then the resulting sequence {{math|''U''<sub>''n''</sub>}} must be the Fibonacci sequence. This is the same as requiring {{mvar|a}} and {{mvar|b}} satisfy the system of equations:
 
<math display=block>\begin{align}
U_n &= a\varphi^n +  b\psi^n \\[3mu]
&= a(\varphi^{n-1} + \varphi^{n-2}) +  b(\psi^{n-1} + \psi^{n-2}) \\[3mu]
&= a\varphi^{n-1} + b\psi^{n-1} + a\varphi^{n-2} + b\psi^{n-2} \\[3mu]
&= U_{n-1} + U_{n-2}.
\end{align}</math>
 
If {{mvar|a}} and {{mvar|b}} are chosen so that {{math|1=''U''<sub>0</sub> = 0}} and {{math|1=''U''<sub>1</sub> = 1}} then the resulting sequence {{math|''U''<sub>''n''</sub>}} must be the Fibonacci sequence. This is the same as requiring {{mvar|a}} and {{mvar|b}} satisfy the system of equations:


<math display=block>
<math display=block>
\left\{\begin{align} a + b &= 0 \\ \varphi a + \psi b &= 1\end{align}\right.
\begin{align} a \varphi^0 + b \psi^0 &= 0 \\ a \varphi^1 + b \psi^1 &= 1\end{align}
</math>
</math>


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producing the required formula.
producing the required formula.


Taking the starting values {{math|''U''<sub>0</sub>}} and {{math|''U''<sub>1</sub>}} to be arbitrary constants, a more general solution is:
Taking the starting values {{math|''U''<sub>0</sub>}} and {{math|''U''<sub>1</sub>}} to be arbitrary constants and solving the system of equations gives the general solution
 
<math display=block> U_n = a\varphi^n + b\psi^n </math>
 
where
 
<math display=block>\begin{align}
<math display=block>\begin{align}
a&=\frac{U_1-U_0\psi}{\sqrt 5}, \\[3mu]
a&=\frac{U_1-U_0\psi}{\sqrt 5}, \\[3mu]
b&=\frac{U_0\varphi-U_1}{\sqrt 5}.
b&=\frac{U_0\varphi-U_1}{\sqrt 5}.
\end{align}</math>
\end{align}</math>
In particular, choosing {{math|1=''a'' = 1}} makes the {{mvar|n}}-th element of the sequence closely approximate the {{mvar|n}}-th power of {{tmath|\varphi}} for large enough values of {{mvar|n}}. This arises when {{math|1=''U''{{sub|0}} = 2}} and {{math|1=''U''{{sub|1}} = 1}}, which produces the sequence of [[Lucas number]]s.


=== Computation by rounding ===
=== Computation by rounding ===
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=== Limit of consecutive quotients ===
=== Limit of consecutive quotients ===
[[Johannes Kepler]] observed that the ratio of consecutive Fibonacci numbers [[convergent sequence|converges]]. He wrote that "as 5 is to 8 so is 8 to 13, practically, and as 8 is to 13, so is 13 to 21 almost", and concluded that these ratios approach the golden ratio <math>\varphi\colon </math> <ref>{{Citation|last=Kepler |first=Johannes |title=A New Year Gift: On Hexagonal Snow |year=1966 |isbn=978-0-19-858120-8 |publisher=Oxford University Press |page= 92}}</ref><ref>{{Citation | title = Strena seu de Nive Sexangula | year = 1611}}</ref>
[[Johannes Kepler]] observed that the ratio of consecutive Fibonacci numbers [[convergent sequence|converges]]. He wrote that "as 5 is to 8 so is 8 to 13, practically, and as 8 is to 13, so is 13 to 21 almost", and concluded that these ratios approach the golden ratio {{tmath|\varphi}}:<ref>{{Citation|last=Kepler |first=Johannes |title=A New Year Gift: On Hexagonal Snow |year=1966 |isbn=978-0-19-858120-8 |publisher=Oxford University Press |page= 92}}</ref><ref>{{Citation | title = Strena seu de Nive Sexangula | year = 1611}}</ref>
<math display=block>\lim_{n\to\infty}\frac{F_{n+1}}{F_n}=\varphi.</math>
<math display=block>\lim_{n\to\infty}\frac{F_{n+1}}{F_n}=\varphi.</math>


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Binet's formula provides a proof that a positive integer {{mvar|x}} is a Fibonacci number [[if and only if]] at least one of <math>5x^2+4</math> or <math>5x^2-4</math> is a [[Square number|perfect square]].<ref>{{Citation | title = Fibonacci is a Square | last1 = Gessel | first1 = Ira | journal = [[The Fibonacci Quarterly]] | volume = 10 | issue = 4 | pages = 417–19 |date=October 1972 | url = https://www.fq.math.ca/Scanned/10-4/advanced10-4.pdf | access-date = 2012-04-11 }}</ref> This is because Binet's formula, which can be written as <math>F_n = (\varphi^n - (-1)^n \varphi^{-n}) / \sqrt{5}</math>, can be multiplied by <math>\sqrt{5} \varphi^n</math> and solved as a [[quadratic equation]] in <math>\varphi^n</math> via the [[quadratic formula]]:
Binet's formula provides a proof that a positive integer {{mvar|x}} is a Fibonacci number [[if and only if]] at least one of <math>5x^2+4</math> or <math>5x^2-4</math> is a [[Square number|perfect square]].<ref>{{Citation | title = Fibonacci is a Square | last1 = Gessel | first1 = Ira | journal = [[The Fibonacci Quarterly]] | volume = 10 | issue = 4 | pages = 417–19 |date=October 1972 | url = https://www.fq.math.ca/Scanned/10-4/advanced10-4.pdf | access-date = 2012-04-11 }}</ref> This is because Binet's formula, which can be written as <math>F_n = (\varphi^n - (-1)^n \varphi^{-n}) / \sqrt{5}</math>, can be multiplied by <math>\sqrt{5} \varphi^n</math> and solved as a [[quadratic equation]] in <math>\varphi^n</math> via the [[quadratic formula]]:


<math display=block>\varphi^n = \frac{F_n\sqrt{5} \pm \sqrt{5{F_n}^2 + 4(-1)^n}}{2}.</math>
<math display=block>\varphi^n = \frac{F_n\sqrt{5} \pm \sqrt{5{F_n}^{\!2} + 4(-1)^n}}{2}.</math>


Comparing this to <math>\varphi^n = F_n \varphi + F_{n-1} = (F_n\sqrt{5} + F_n + 2 F_{n-1})/2</math>, it follows that
Comparing this to <math>\varphi^n = F_n \varphi + F_{n-1} = (F_n\sqrt{5} + F_n + 2 F_{n-1})/2</math>, it follows that
: <math display=block>5{F_n}^2 + 4(-1)^n = (F_n + 2F_{n-1})^2\,.</math>
: <math display=block>5{F_n}^{\!2} + 4(-1)^n = (F_n + 2F_{n-1})^2\,.</math>
In particular, the left-hand side is a perfect square.
In particular, the left-hand side is a perfect square.


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As the initial value is
As the initial value is
<math display=block>\vec F_0=\begin{pmatrix} 1 \\ 0 \end{pmatrix}=\frac{1}{\sqrt{5}}\vec{\mu}\,-\,\frac{1}{\sqrt{5}}\vec{\nu},</math>
<math display=block>
 
  \vec F_0=\begin{pmatrix} 1 \\ 0 \end{pmatrix}=\frac{1}{\sqrt{5}}\vec{\mu}\,-\,\frac{1}{\sqrt{5}}\vec{\nu},
</math>
it follows that the {{mvar|n}}th element is
it follows that the {{mvar|n}}th element is
<math display=block>\begin{align}
<math display=block>\begin{align}
\vec F_n\ &= \frac{1}{\sqrt{5}}A^n\vec\mu-\frac{1}{\sqrt{5}}A^n\vec\nu \\
  \vec F_n\ &= \frac{1}{\sqrt{5}}A^n\vec\mu-\frac{1}{\sqrt{5}}A^n\vec\nu \\
&= \frac{1}{\sqrt{5}}\varphi^n\vec\mu - \frac{1}{\sqrt{5}}(-\varphi)^{-n}\vec\nu \\
  &= \frac{1}{\sqrt{5}}\varphi^n\vec\mu - \frac{1}{\sqrt{5}}(-\varphi)^{-n}\vec\nu \\
&= \cfrac{1}{\sqrt{5}}\left(\cfrac{1+\sqrt{5}}{2}\right)^{\!n}\begin{pmatrix} \varphi \\ 1 \end{pmatrix} \,-\, \cfrac{1}{\sqrt{5}}\left(\cfrac{1-\sqrt{5}}{2}\right)^{\!n}\begin{pmatrix}{c} -\varphi^{-1} \\ 1 \end{pmatrix}.
  &= \cfrac{1}{\sqrt{5}}\left(\cfrac{1+\sqrt{5}}{2}\right)^{\!n}\begin{pmatrix} \varphi \\ 1 \end{pmatrix} \,-\, \cfrac{1}{\sqrt{5}}\left(\cfrac{1-\sqrt{5}}{2}\right)^{\!n}\begin{pmatrix}{c} -\varphi^{-1} \\ 1 \end{pmatrix}.
\end{align}</math>
\end{align}</math>


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Equivalently, the same computation may be performed by [[Matrix diagonalization|diagonalization]] of {{math|'''A'''}} through use of its [[eigendecomposition]]:
Equivalently, the same computation may be performed by [[Matrix diagonalization|diagonalization]] of {{math|'''A'''}} through use of its [[eigendecomposition]]:
 
<math display=block>\begin{align}  
<math display=block>\begin{align} A & = S\Lambda S^{-1}, \\[3mu]
  A & = S\Lambda S^{-1}, \\[3mu]
A^n & = S\Lambda^n S^{-1},
  A^n & = S\Lambda^n S^{-1},
\end{align}</math>
\end{align}</math>
where
where
<math display=block>
<math display=block>
\Lambda=\begin{pmatrix} \varphi & 0 \\ 0 & -\varphi^{-1}\! \end{pmatrix}, \quad
  \Lambda=\begin{pmatrix} \varphi & 0 \\ 0 & -\varphi^{-1}\! \end{pmatrix}, \quad
S=\begin{pmatrix} \varphi & -\varphi^{-1} \\ 1 & 1 \end{pmatrix}.
  S=\begin{pmatrix} \varphi & -\varphi^{-1} \\ 1 & 1 \end{pmatrix}.
</math>
</math>
The closed-form expression for the {{mvar|n}}th element in the Fibonacci series is therefore given by
The closed-form expression for the {{mvar|n}}th element in the Fibonacci series is therefore given by
 
<math display=block>\begin{align}  
<math display=block>\begin{align} \begin{pmatrix} F_{n+1} \\ F_n \end{pmatrix} & = A^{n} \begin{pmatrix} F_1 \\ F_0 \end{pmatrix}\ \\
  \begin{pmatrix} F_{n+1} \\ F_n \end{pmatrix} & =  
& = S \Lambda^n S^{-1} \begin{pmatrix} F_1 \\ F_0 \end{pmatrix} \\
  A^{n} \begin{pmatrix} F_1 \\ F_0 \end{pmatrix}\  
& = S \begin{pmatrix} \varphi^n & 0 \\ 0 & (-\varphi)^{-n} \end{pmatrix} S^{-1} \begin{pmatrix} F_1 \\ F_0 \end{pmatrix} \\
  \\ & = S \Lambda^n S^{-1} \begin{pmatrix} F_1 \\ F_0 \end{pmatrix}  
& = \begin{pmatrix} \varphi & -\varphi^{-1} \\ 1 & 1 \end{pmatrix}
  \\ & = S \begin{pmatrix} \varphi^n & 0 \\ 0 & (-\varphi)^{-n} \end{pmatrix} S^{-1}  
    \begin{pmatrix} F_1 \\ F_0 \end{pmatrix}  
  \\ & = \begin{pmatrix} \varphi & -\varphi^{-1} \\ 1 & 1 \end{pmatrix}
     \begin{pmatrix}\varphi^n & 0 \\ 0 & (-\varphi)^{-n} \end{pmatrix}
     \begin{pmatrix}\varphi^n & 0 \\ 0 & (-\varphi)^{-n} \end{pmatrix}
     \frac{1}{\sqrt{5}}\begin{pmatrix} 1 & \varphi^{-1} \\ -1 & \varphi \end{pmatrix} \begin{pmatrix} 1 \\ 0 \end{pmatrix},
     \frac{1}{\sqrt{5}}\begin{pmatrix} 1 & \varphi^{-1} \\ -1 & \varphi \end{pmatrix}  
    \begin{pmatrix} 1 \\ 0 \end{pmatrix},
\end{align}</math>
\end{align}</math>
which again yields
which again yields
<math display=block>F_n = \cfrac{\varphi^n-(-\varphi)^{-n}}{\sqrt{5}}.</math>
<math display=block>
  F_n = \cfrac{\varphi^n-(-\varphi)^{-n}}{\sqrt{5}}.
</math>


The matrix {{math|'''A'''}} has a [[determinant]] of −1, and thus it is a 2&thinsp;×&thinsp;2 [[unimodular matrix]].
The matrix {{math|'''A'''}} has a [[determinant]] of −1, and thus it is a 2&thinsp;×&thinsp;2 [[unimodular matrix]].


This property can be understood in terms of the [[continued fraction]] representation for the golden ratio {{mvar|φ}}:
This property can be understood in terms of the [[continued fraction]] representation for the golden ratio {{mvar|φ}}:
 
<math display=block>
<math display=block>\varphi = 1 + \cfrac{1}{1 + \cfrac{1}{1 + \cfrac{1}{1 + \ddots}}}.</math>
  \varphi = 1 + \cfrac{1}{1 + \cfrac{1}{1 + \cfrac{1}{1 + \ddots}}}.
 
</math>
The [[convergent (continued fraction)|convergents]] of the continued fraction for {{mvar|φ}} are ratios of successive Fibonacci numbers: {{math|1=''φ''<sub>''n''</sub> = ''F''<sub>''n''+1</sub> / ''F''<sub>''n''</sub>}} is the {{mvar|n}}-th convergent, and the {{math|(''n''&thinsp;+&thinsp;1)}}-st convergent can be found from the recurrence relation {{math|1=''φ''<sub>''n''+1</sub> = 1 + 1 / ''φ''<sub>''n''</sub>}}.<ref>{{Cite web |title=The Golden Ratio, Fibonacci Numbers and Continued Fractions. |url=https://nrich.maths.org/2737 |access-date=2024-03-22 |website=nrich.maths.org |language=en}}</ref> The matrix formed from successive convergents of any continued fraction has a determinant of +1 or −1. The matrix representation gives the following closed-form expression for the Fibonacci numbers:
The [[convergent (continued fraction)|convergents]] of the continued fraction for {{mvar|φ}} are ratios of successive Fibonacci numbers: {{math|1=''φ''<sub>''n''</sub> = ''F''<sub>''n''+1</sub> / ''F''<sub>''n''</sub>}} is the {{mvar|n}}-th convergent, and the {{math|(''n''&thinsp;+&thinsp;1)}}-st convergent can be found from the recurrence relation {{math|1=''φ''<sub>''n''+1</sub> = 1 + 1 / ''φ''<sub>''n''</sub>}}.<ref>{{Cite web |title=The Golden Ratio, Fibonacci Numbers and Continued Fractions. |url=https://nrich.maths.org/2737 |access-date=2024-03-22 |website=nrich.maths.org |language=en}}</ref> The matrix formed from successive convergents of any continued fraction has a determinant of +1 or −1. The matrix representation gives the following closed-form expression for the Fibonacci numbers:
 
<math display=block>
<math display=block>\begin{pmatrix} 1 & 1 \\ 1 & 0 \end{pmatrix}^n = \begin{pmatrix} F_{n+1} & F_n \\ F_n & F_{n-1} \end{pmatrix}.</math>
  \begin{pmatrix} 1 & 1 \\ 1 & 0 \end{pmatrix}^n =  
 
  \begin{pmatrix} F_{n+1} & F_n \\ F_n & F_{n-1} \end{pmatrix}.
For a given {{mvar|n}}, this matrix can be computed in {{math|''O''(log ''n'')}} arithmetic operations, using the [[exponentiation by squaring]] method.
</math>
For a given {{mvar|n}}, this matrix can be computed in {{math|''O''(log ''n'')}} arithmetic operations,{{efn|This counts [[arbitrary-precision arithmetic]] operations as being {{math|''O''(1)}}. If taking the bitlength into account, exponentiation by squaring is still a marked improvement, but overall complexity is dominated by the very last multiplication step; there are {{math|''O''(''n'')}} digits in the result, and the task requires producing all of them.}} using the [[exponentiation by squaring]] method.


Taking the determinant of both sides of this equation yields [[Cassini's identity]],
Taking the determinant of both sides of this equation yields [[Cassini's identity]],
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[[File:Fibonacci Squares.svg|frameless|260x260px]]
[[File:Fibonacci Squares.svg|frameless|260x260px]]
=== Symbolic method ===
The sequence <math>(F_n)_{n\in\mathbb N}</math> is also considered using the [[symbolic method (combinatorics)|symbolic method]].<ref>{{citation |last1=Flajolet |first1=Philippe |last2=Sedgewick |first2=Robert |title=Analytic Combinatorics|title-link= Analytic Combinatorics |date=2009 |publisher=Cambridge University Press |isbn=978-0521898065 |page=42}}</ref> More precisely, this sequence corresponds to a [[specifiable combinatorial class]]. The specification of this sequence is <math>\operatorname{Seq}(\mathcal{Z+Z^2})</math>. Indeed, as stated above, the <math>n</math>-th Fibonacci number equals the number of [[Composition (combinatorics)|combinatorial compositions]] (ordered [[integer partition|partitions]]) of <math>n-1</math> using terms 1 and 2.
It follows that the [[ordinary generating function]] of the Fibonacci sequence, <math>\sum_{i=0}^\infty F_iz^i</math>, is the [[rational function]] <math>\frac{z}{1-z-z^2}.</math>


=== Induction proofs ===
=== Induction proofs ===
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=== Cassini's and Catalan's identities ===
=== Cassini's and Catalan's identities ===
{{Main|Cassini and Catalan identities}}
{{Main|Cassini and Catalan identities}}
Cassini's identity states that
Cassini's identity states that
<math display=block>{F_n}^2 - F_{n+1}F_{n-1} = (-1)^{n-1}</math>
<math display=block>{F_n}^2 - F_{n+1}F_{n-1} = (-1)^{n-1}</math>
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== Generating function ==
== Generating function ==
The [[generating function]] of the Fibonacci sequence is the [[power series]]
The [[ordinary generating function]] of the Fibonacci sequence is the [[power series]]


<math display=block>
<math display=block>
s(z) = \sum_{k=0}^\infty F_k z^k = 0 + z + z^2 + 2z^3 + 3z^4 + 5z^5 + \dots.
s(z) = \sum_{k=0}^\infty F_k z^k = 0 + z + z^2 + 2z^3 + 3z^4 + 5z^5 + \cdots.
</math>
</math>


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<math display=block>s(z) = \frac{1}{\sqrt5}\left(\frac{1}{1 - \varphi z} - \frac{1}{1 - \psi z}\right)</math>
<math display=block>s(z) = \frac{1}{\sqrt5}\left(\frac{1}{1 - \varphi z} - \frac{1}{1 - \psi z}\right)</math>
where <math display=inline>\varphi = \tfrac12\left(1 + \sqrt{5}\right)</math> is the golden ratio and <math>\psi = \tfrac12\left(1 - \sqrt{5}\right)</math> is its [[Conjugate (square roots)|conjugate]].
where <math display=inline>\varphi = \tfrac12\left(1 + \sqrt{5}\right)</math> is the golden ratio and <math>\psi = \tfrac12\left(1 - \sqrt{5}\right)</math> is its [[Conjugate (square roots)|conjugate]].
The related function <math display=inline>z \mapsto -s\left(-1/z\right)</math> is the generating function for the [[negafibonacci]] numbers, and <math>s(z)</math> satisfies the [[functional equation]]
<math display=block>s(z) = s\!\left(-\frac{1}{z}\right).</math>


Using <math>z</math> equal to any of 0.01, 0.001, 0.0001, etc. lays out the first Fibonacci numbers in the decimal expansion of <math>s(z)</math>. For example, <math>s(0.001) = \frac{0.001}{0.998999} = \frac{1000}{998999} = 0.001001002003005008013021\ldots.</math>
Using <math>z</math> equal to any of 0.01, 0.001, 0.0001, etc. lays out the first Fibonacci numbers in the decimal expansion of <math>s(z)</math>. For example, <math>s(0.001) = \frac{0.001}{0.998999} = \frac{1000}{998999} = 0.001001002003005008013021\ldots.</math>
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  | hdl-access = free
  | hdl-access = free
  }}. Williams calls this property "well known".</ref>
  }}. Williams calls this property "well known".</ref>
<math display=block>p \mid F_{p \;-\, \left(\frac{5}{p}\right)}.</math>
<math display=block>p \mid F_{p \,-~\! \left(\frac{5}{p}\right)}.</math>


=== Primality testing ===
=== Primality testing ===
The above formula can be used as a [[primality test]] in the sense that if
The above formula can be used as a [[primality test]] in the sense that if
<math display=block>n \mid F_{n \;-\, \left(\frac{5}{n}\right)},</math>
<math display=block>n \mid F_{n \,-~\! \left(\frac{5}{n}\right)},</math>
where the Legendre symbol has been replaced by the [[Jacobi symbol]], then this is evidence that {{mvar|n}} is a prime, and if it fails to hold, then {{mvar|n}} is definitely not a prime. If {{mvar|n}} is [[composite number|composite]] and satisfies the formula, then {{mvar|n}} is a ''Fibonacci pseudoprime''. When {{mvar|m}} is large{{snd}}say a 500-[[bit]] number{{snd}}then we can calculate {{math|''F''<sub>''m''</sub> (mod ''n'')}} efficiently using the matrix form. Thus
where the Legendre symbol has been replaced by the [[Jacobi symbol]], then this is evidence that {{mvar|n}} is a prime, and if it fails to hold, then {{mvar|n}} is definitely not a prime. If {{mvar|n}} is [[composite number|composite]] and satisfies the formula, then {{mvar|n}} is a ''Fibonacci pseudoprime''. When {{mvar|m}} is large{{snd}}say a 500-[[bit]] number{{snd}}then we can calculate {{math|''F''<sub>''m''</sub> (mod ''n'')}} efficiently using the matrix form. Thus


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It is not known whether there exists a prime {{mvar|p}} such that
It is not known whether there exists a prime {{mvar|p}} such that


<math display=block>F_{p-\left(\frac{p}{5}\right)} \equiv 0 \pmod{p^2}.</math>
<math display=block>F_{p\,-~\!\left(\frac{p}{5}\right)} \equiv 0 \pmod{p^2}.</math>


Such primes (if there are any) would be called [[Wall–Sun–Sun prime]]s.
Such primes (if there are any) would be called [[Wall–Sun–Sun prime]]s.
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The Fibonacci numbers can be found in different ways among the set of [[binary numeral system|binary]] [[String (computer science)|strings]], or equivalently, among the [[subset]]s of a given set.
The Fibonacci numbers can be found in different ways among the set of [[binary numeral system|binary]] [[String (computer science)|strings]], or equivalently, among the [[subset]]s of a given set.
* The number of binary strings of length {{mvar|n}} without consecutive {{math|1}}s is the Fibonacci number {{math|''F''<sub>''n''+2</sub>}}. For example, out of the 16 binary strings of length 4, there are {{math|1=''F''<sub>6</sub> = 8}} without consecutive {{math|1}}s—they are 0000, 0001, 0010, 0100, 0101, 1000, 1001, and 1010. Such strings are the binary representations of [[Fibbinary number]]s. Equivalently, {{math|''F''<sub>''n''+2</sub>}} is the number of subsets {{mvar|S}} of {{math|{{mset|1, ..., ''n''}}}} without consecutive integers, that is, those {{mvar|S}} for which {{math|{{mset|''i'', ''i'' + 1}} ⊈ ''S''}} for every {{mvar|i}}. A [[bijection]] with the sums to {{math|''n''+1}} is to replace 1 with 0 and 2 with 10, and drop the last zero.
* The number of binary strings of length {{mvar|n}} without consecutive {{mono|1}}s is the Fibonacci number {{math|''F''<sub>''n''+2</sub>}}. For example, out of the 16 binary strings of length 4, there are {{math|1=''F''<sub>6</sub> = 8}} without consecutive {{math|1}}s—they are {{mono|0000}}, {{mono|0001}}, {{mono|0010}}, {{mono|0100}}, {{mono|0101}}, {{mono|1000}}, {{mono|1001}}, and {{mono|1010}}. Such strings are the binary representations of [[Fibbinary number]]s. Equivalently, {{math|''F''<sub>''n''+2</sub>}} is the number of subsets {{mvar|S}} of {{math|{{mset|1, ..., ''n''}}}} without consecutive integers, that is, those {{mvar|S}} for which {{math|{{mset|''i'', ''i'' + 1}} ⊈ ''S''}} for every {{mvar|i}}. A [[bijection]] with the sums to {{math|''n''+1}} is to replace 1 with {{mono|0}} and 2 with {{mono|10}}, and drop the last zero.
* The number of binary strings of length {{mvar|n}} without an odd number of consecutive {{math|1}}s is the Fibonacci number {{math|''F''<sub>''n''+1</sub>}}. For example, out of the 16 binary strings of length 4, there are {{math|1=''F''<sub>5</sub> = 5}} without an odd number of consecutive {{math|1}}s—they are 0000, 0011, 0110, 1100, 1111. Equivalently, the number of subsets {{mvar|S}} of {{math|{{mset|1, ..., ''n''}}}} without an odd number of consecutive integers is {{math|''F''<sub>''n''+1</sub>}}. A bijection with the sums to {{mvar|n}} is to replace 1 with 0 and 2 with 11.
* The number of binary strings of length {{mvar|n}} without an odd number of consecutive {{mono|1}}s is the Fibonacci number {{math|''F''<sub>''n''+1</sub>}}. For example, out of the 16 binary strings of length 4, there are {{math|1=''F''<sub>5</sub> = 5}} without an odd number of consecutive {{mono|1}}s—they are {{mono|0000}}, {{mono|0011}}, {{mono|0110}}, {{mono|1100}}, {{mono|1111}}. Equivalently, the number of subsets {{mvar|S}} of {{math|{{mset|1, ..., ''n''}}}} without an odd number of consecutive integers is {{math|''F''<sub>''n''+1</sub>}}. A bijection with the sums to {{mvar|n}} is to replace 1 with {{mono|0}} and 2 with {{mono|11}}.
* The number of binary strings of length {{mvar|n}} without an even number of consecutive {{math|0}}s or {{math|1}}s is {{math|2''F''<sub>''n''</sub>}}. For example, out of the 16 binary strings of length 4, there are {{math|1=2''F''<sub>4</sub> = 6}} without an even number of consecutive {{math|0}}s or {{math|1}}s—they are 0001, 0111, 0101, 1000, 1010, 1110. There is an equivalent statement about subsets.
* The number of binary strings of length {{mvar|n}} without an even number of consecutive {{mono|0}}s or {{mono|1}}s is {{math|2''F''<sub>''n''</sub>}}. For example, out of the 16 binary strings of length 4, there are {{math|1=2''F''<sub>4</sub> = 6}} without an even number of consecutive {{mono|0}}s or {{mono|1}}s—they are {{mono|0001}}, {{mono|0111}}, {{mono|0101}}, {{mono|1000}}, {{mono|1010}}, {{mono|1110}}. There is an equivalent statement about subsets.
* [[Yuri Matiyasevich]] was able to show that the Fibonacci numbers can be defined by a [[Diophantine equation]], which led to [[Matiyasevich's theorem|his solving]] [[Hilbert's tenth problem]].<ref>{{citation|title=Review of Yuri V. Matiyasevich, ''Hibert's Tenth Problem''|journal=Modern Logic|first=Valentina|last=Harizanov|author-link=Valentina Harizanov|volume=5|issue=3|year=1995|pages=345–55|url=https://projecteuclid.org/euclid.rml/1204900767}}</ref>
* [[Yuri Matiyasevich]] was able to show that the Fibonacci numbers can be defined by a [[Diophantine equation]], which led to [[Matiyasevich's theorem|his solving]] [[Hilbert's tenth problem]].<ref>{{citation|title=Review of Yuri V. Matiyasevich, ''Hibert's Tenth Problem''|journal=Modern Logic|first=Valentina|last=Harizanov|author-link=Valentina Harizanov|volume=5|issue=3|year=1995|pages=345–55|url=https://projecteuclid.org/euclid.rml/1204900767}}</ref>
* The Fibonacci numbers are also an example of a [[complete sequence]]. This means that every positive integer can be written as a sum of Fibonacci numbers, where any one number is used once at most.
* The Fibonacci numbers are also an example of a [[complete sequence]]. This means that every positive integer can be written as a sum of Fibonacci numbers, where any one number is used once at most.
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[[File:FibonacciChamomile.PNG|thumb|[[Yellow chamomile]] head showing the arrangement in 21 (blue) and 13 (cyan) spirals. Such arrangements involving consecutive Fibonacci numbers appear in a wide variety of plants.]]
[[File:FibonacciChamomile.PNG|thumb|[[Yellow chamomile]] head showing the arrangement in 21 (blue) and 13 (cyan) spirals. Such arrangements involving consecutive Fibonacci numbers appear in a wide variety of plants.]]


Fibonacci sequences appear in biological settings,<ref>{{Citation |first1=S |last1=Douady |first2=Y |last2=Couder |title=Phyllotaxis as a Dynamical Self Organizing Process |journal=Journal of Theoretical Biology |year=1996 |issue=3 |pages=255–74 |url=http://www.math.ntnu.no/~jarlet/Douady96.pdf |doi=10.1006/jtbi.1996.0026 |volume=178 |url-status=dead |archive-url=https://web.archive.org/web/20060526054108/http://www.math.ntnu.no/~jarlet/Douady96.pdf |archive-date=2006-05-26 }}</ref> such as branching in trees, [[Phyllotaxis|arrangement of leaves on a stem]], the fruitlets of a [[pineapple]],<ref>{{Citation | first1=Judy |last1=Jones | first2=William | last2=Wilson |title=An Incomplete Education |publisher=Ballantine Books |year=2006 |isbn=978-0-7394-7582-9 |page=544 |chapter=Science}}</ref> the flowering of [[artichoke]], the arrangement of a [[pine cone]],<ref>{{Citation| first=A | last=Brousseau |title=Fibonacci Statistics in Conifers | journal=[[Fibonacci Quarterly]] |year=1969 |issue=7 |pages=525–32}}</ref> and the family tree of [[honeybee]]s.<ref>{{citation|url = https://www.cs4fn.org/maths/bee-davinci.php |work = Maths | publisher = Computer Science For Fun: CS4FN |title = Marks for the da Vinci Code: B–}}</ref><ref>{{Citation|first1=T.C.|last1=Scott|first2=P.|last2=Marketos| url = http://www-history.mcs.st-andrews.ac.uk/Publications/fibonacci.pdf | title = On the Origin of the Fibonacci Sequence | publisher = [[MacTutor History of Mathematics archive]], University of St Andrews| date = March 2014}}</ref> [[Kepler]] pointed out the presence of the Fibonacci sequence in nature, using it to explain the ([[golden ratio]]-related) [[pentagon]]al form of some flowers.{{sfn|Livio|2003|p=110}} Field [[Leucanthemum vulgare|daisies]] most often have petals in counts of Fibonacci numbers.{{sfn|Livio|2003|pp=112–13}} In 1830, [[Karl Friedrich Schimper]] and [[Alexander Braun]] discovered that the [[Parastichy|parastichies]] (spiral [[phyllotaxis]]) of plants were frequently expressed as fractions involving Fibonacci numbers.<ref>{{Citation |first =Franck |last = Varenne |title = Formaliser le vivant - Lois, Théories, Modèles | access-date = 2022-10-30| url = https://www.numilog.com/LIVRES/ISBN/9782705670894.Livre | page = 28 | date = 2010| isbn = 9782705678128|publisher = Hermann|quote = En 1830, K. F. Schimper et A. Braun [...]. Ils montraient que si l'on représente cet angle de divergence par une fraction reflétant le nombre de tours par feuille ([...]), on tombe régulièrement sur un des nombres de la suite de Fibonacci pour le numérateur [...].|language = fr}}</ref>
Fibonacci sequences appear in biological settings,<ref>{{Citation |first1=S |last1=Douady |first2=Y |last2=Couder |title=Phyllotaxis as a Dynamical Self Organizing Process |journal=Journal of Theoretical Biology |year=1996 |issue=3 |pages=255–74 |url=http://www.math.ntnu.no/~jarlet/Douady96.pdf |doi=10.1006/jtbi.1996.0026 |volume=178 |url-status=dead |archive-url=https://web.archive.org/web/20060526054108/http://www.math.ntnu.no/~jarlet/Douady96.pdf |archive-date=2006-05-26 }}</ref> such as branching in trees, [[Phyllotaxis|arrangement of leaves on a stem]], the fruitlets of a [[pineapple]],<ref>{{Citation | first1=Judy |last1=Jones | first2=William | last2=Wilson |title=An Incomplete Education |publisher=Ballantine Books |year=2006 |isbn=978-0-7394-7582-9 |page=544 |chapter=Science}}</ref> the flowering of [[artichoke]], the leaves of the spiral aloe<ref>{{Cite web |title=The Wonder of Fibonacci in our Gardens {{!}} UC Master Gardeners of San Mateo & San Francisco Counties |url=https://ucanr.edu/blog/uc-master-gardeners-san-mateo-san-francisco-counties/article/wonder-fibonacci-our-gardens |access-date=2025-11-18 |website=ucanr.edu |language=en}}</ref> (Aloe polyphylla), the arrangement of a [[pine cone]],<ref>{{Citation| first=A | last=Brousseau |title=Fibonacci Statistics in Conifers | journal=[[Fibonacci Quarterly]] |year=1969 |issue=7 |pages=525–32}}</ref> and the family tree of [[honeybee]]s.<ref>{{citation|url = https://www.cs4fn.org/maths/bee-davinci.php |work = Maths | publisher = Computer Science For Fun: CS4FN |title = Marks for the da Vinci Code: B–}}</ref><ref>{{Citation|first1=T.C.|last1=Scott|first2=P.|last2=Marketos| url = http://www-history.mcs.st-andrews.ac.uk/Publications/fibonacci.pdf | title = On the Origin of the Fibonacci Sequence | publisher = [[MacTutor History of Mathematics archive]], University of St Andrews| date = March 2014}}</ref> [[Kepler]] pointed out the presence of the Fibonacci sequence in nature, using it to explain the ([[golden ratio]]-related) [[pentagon]]al form of some flowers.{{sfn|Livio|2003|p=110}} Field [[Leucanthemum vulgare|daisies]] most often have petals in counts of Fibonacci numbers.{{sfn|Livio|2003|pp=112–13}} In 1830, [[Karl Friedrich Schimper]] and [[Alexander Braun]] discovered that the [[Parastichy|parastichies]] (spiral [[phyllotaxis]]) of plants were frequently expressed as fractions involving Fibonacci numbers.<ref>{{Citation |first =Franck |last = Varenne |title = Formaliser le vivant - Lois, Théories, Modèles | access-date = 2022-10-30| url = https://www.numilog.com/LIVRES/ISBN/9782705670894.Livre | page = 28 | date = 2010| isbn = 9782705678128|publisher = Hermann|quote = En 1830, K. F. Schimper et A. Braun [...]. Ils montraient que si l'on représente cet angle de divergence par une fraction reflétant le nombre de tours par feuille ([...]), on tombe régulièrement sur un des nombres de la suite de Fibonacci pour le numérateur [...].|language = fr}}</ref>


[[Przemysław Prusinkiewicz]] advanced the idea that real instances can in part be understood as the expression of certain algebraic constraints on [[free group]]s, specifically as certain [[L-system|Lindenmayer grammars]].<ref>{{Citation|first1 = Przemyslaw |last1 = Prusinkiewicz | first2 = James | last2 = Hanan| title = Lindenmayer Systems, Fractals, and Plants (Lecture Notes in Biomathematics) |publisher= [[Springer Science+Business Media|Springer-Verlag]] |year=1989 |isbn=978-0-387-97092-9}}</ref>
[[Przemysław Prusinkiewicz]] advanced the idea that real instances can in part be understood as the expression of certain algebraic constraints on [[free group]]s, specifically as certain [[L-system|Lindenmayer grammars]].<ref>{{Citation|first1 = Przemyslaw |last1 = Prusinkiewicz | first2 = James | last2 = Hanan| title = Lindenmayer Systems, Fractals, and Plants (Lecture Notes in Biomathematics) |publisher= [[Springer Science+Business Media|Springer-Verlag]] |year=1989 |isbn=978-0-387-97092-9}}</ref>
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  }}</ref>
  }}</ref>
* Brasch et al. 2012 show how a generalized Fibonacci sequence also can be connected to the field of [[economics]].<ref name="Brasch et al. 2012">{{Citation| first1 =T. von | last1 = Brasch | first2 = J. | last2 = Byström | first3 = L.P. | last3 = Lystad| title= Optimal Control and the Fibonacci Sequence |journal = Journal of Optimization Theory and Applications |year=2012 |issue=3 |pages= 857–78 |doi = 10.1007/s10957-012-0061-2
* Brasch et al. 2012 show how a generalized Fibonacci sequence also can be connected to the field of [[economics]].<ref name="Brasch et al. 2012">{{Citation| first1 =T. von | last1 = Brasch | first2 = J. | last2 = Byström | first3 = L.P. | last3 = Lystad| title= Optimal Control and the Fibonacci Sequence |journal = Journal of Optimization Theory and Applications |year=2012 |issue=3 |pages= 857–78 |doi = 10.1007/s10957-012-0061-2
|volume=154 | hdl = 11250/180781 | s2cid = 8550726 | url = https://urn.kb.se/resolve?urn=urn:nbn:se:ltu:diva-24073 | hdl-access = free }}</ref> In particular, it is shown how a generalized Fibonacci sequence enters the control function of finite-horizon dynamic optimisation problems with one state and one control variable. The procedure is illustrated in an example often referred to as the Brock–Mirman economic growth model.
|volume=154 | hdl = 11250/180781 | s2cid = 8550726 | url = https://urn.kb.se/resolve?urn=urn:nbn:se:ltu:diva-24073 | hdl-access = free }}</ref> In particular, it is shown how a generalized Fibonacci sequence enters the control function of finite-horizon dynamic optimisation problems with one state and one control variable. The procedure is illustrated in an example often referred to as the Brock–Mirman economic growth model.
* [[Mario Merz]] included the Fibonacci sequence in some of his artworks beginning in 1970.{{sfn|Livio|2003|p=176}}
* [[Mario Merz]] included the Fibonacci sequence in some of his artworks beginning in 1970.{{sfn|Livio|2003|p=176}}
* [[Joseph Schillinger]] (1895–1943) developed [[Schillinger System|a system of composition]] which uses Fibonacci intervals in some of its melodies; he viewed these as the musical counterpart to the elaborate harmony evident within nature.{{sfn|Livio|2003|p=193}} See also {{slink|Golden ratio|Music}}.
* [[Joseph Schillinger]] (1895–1943) developed [[Schillinger System|a system of composition]] which uses Fibonacci intervals in some of its melodies; he viewed these as the musical counterpart to the elaborate harmony evident within nature.{{sfn|Livio|2003|p=193}} See also {{slink|Golden ratio|Music}}.
* In [[software development]], Fibonacci numbers are often used by [[Agile management|agile]] teams operating under the [[Scrum (software development)|Scrum]] framework to size their [[product backlog]] items.<ref>{{cite web |last1=Kathuria |first1=Madhur |title=A Guide to Using the Fibonacci Sequence in Scrum |url=https://resources.scrumalliance.org/Article/guide-using-fibonacci-sequence-scrum |website=Scrum Alliance |access-date=8 August 2025}}</ref>


== See also ==
== See also ==
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{{Fibonacci}}
{{Fibonacci}}
{{Authority control}}
{{Authority control}}
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{{Interwiki extra|qid=Q47577}}


[[Category:Fibonacci numbers| ]]
[[Category:Fibonacci numbers| ]]
[[Category:Articles containing proofs]]
[[Category:Articles containing proofs]]
[[Category:Integer sequences]]
[[Category:Integer sequences]]

Latest revision as of 16:58, 18 November 2025

Template:Short description Script error: No such module "For". Template:Pp-pc

In mathematics, the Fibonacci sequence is a sequence in which each element is the sum of the two elements that precede it. Numbers that are part of the Fibonacci sequence are known as Fibonacci numbers, commonly denoted Template:Math. Many writers begin the sequence with 0 and 1, although some authors start it from 1 and 1[1][2] and some (as did Fibonacci) from 1 and 2. Starting from 0 and 1, the sequence begins

0, 1, 1, 2, 3, 5, 8, 13, 21, 34, 55, 89, 144, ... (sequence A000045 in the OEIS)
File:Fibonacci Squares.svg
A tiling with squares whose side lengths are successive Fibonacci numbers: 1, 1, 2, 3, 5, 8, 13 and 21

The Fibonacci numbers were first described in Indian mathematics as early as 200 BC in work by Pingala on enumerating possible patterns of Sanskrit poetry formed from syllables of two lengths.[3][4][5] They are named after the Italian mathematician Leonardo of Pisa, also known as Fibonacci, who introduced the sequence to Western European mathematics in his 1202 book Script error: No such module "Lang"..Template:Sfn

Fibonacci numbers appear unexpectedly often in mathematics, so much so that there is an entire journal dedicated to their study, the Fibonacci Quarterly. Applications of Fibonacci numbers include computer algorithms such as the Fibonacci search technique and the Fibonacci heap data structure, and graphs called Fibonacci cubes used for interconnecting parallel and distributed systems. They also appear in biological settings, such as branching in trees, the arrangement of leaves on a stem, the fruit sprouts of a pineapple, the flowering of an artichoke, and the arrangement of a pine cone's bracts, though they do not occur in all species.

Fibonacci numbers are also strongly related to the golden ratio: Binet's formula expresses the Template:Mvar-th Fibonacci number in terms of Template:Mvar and the golden ratio, and implies that the ratio of two consecutive Fibonacci numbers tends to the golden ratio as Template:Mvar increases. Fibonacci numbers are also closely related to Lucas numbers, which obey the same recurrence relation and with the Fibonacci numbers form a complementary pair of Lucas sequences.

Definition

File:Fibonacci Spiral.svg
The Fibonacci spiral: an approximation of the golden spiral created by drawing circular arcs connecting the opposite corners of squares in the Fibonacci tiling (see preceding image)

The Fibonacci numbers may be defined by the recurrence relationTemplate:Sfn F0=0,F1=1, and Fn=Fn1+Fn2 for Template:Math.

Under some older definitions, the value F0=0 is omitted, so that the sequence starts with F1=F2=1, and the recurrence Fn=Fn1+Fn2 is valid for Template:Math.Template:SfnTemplate:Sfn

The first 20 Fibonacci numbers Template:Math are:

Template:Math Template:Math Template:Math Template:Math Template:Math Template:Math Template:Math Template:Math Template:Math Template:Math Template:Math Template:Math Template:Math Template:Math Template:Math Template:Math Template:Math Template:Math Template:Math Template:Math
0 1 1 2 3 5 8 13 21 34 55 89 144 233 377 610 987 1597 2584 4181

The Fibonacci sequence can be extended to negative integer indices by following the same recurrence relation in the negative direction (sequence A039834 in the OEIS): Template:Tmath, Template:Tmath, and Template:Tmath for Template:Math. Nearly all properties of Fibonacci numbers do not depend upon whether the indices are positive or negative. The values for positive and negative indices obey the relation:[6] Fn=(1)n+1Fn.

History

India

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File:Fibonacci Sanskrit prosody.svg
Thirteen (Template:Math) ways of arranging long and short syllables in a cadence of length six. Eight (Template:Math) end with a short syllable and five (Template:Math) end with a long syllable.

The Fibonacci sequence appears in Indian mathematics, in connection with Sanskrit prosody.[4][7]Template:Sfn In the Sanskrit poetic tradition, there was interest in enumerating all patterns of long (L) syllables of 2 units duration, juxtaposed with short (S) syllables of 1 unit duration. Counting the different patterns of successive L and S with a given total duration results in the Fibonacci numbers: the number of patterns of duration Template:Mvar units is Template:Math.[5]

Knowledge of the Fibonacci sequence was expressed as early as Pingala (Template:Circa 450 BC–200 BC). Singh cites Pingala's cryptic formula misrau cha ("the two are mixed") and scholars who interpret it in context as saying that the number of patterns for Template:Mvar beats (Template:Math) is obtained by adding one [S] to the Template:Math cases and one [L] to the Template:Math cases.[8] Bharata Muni also expresses knowledge of the sequence in the Natya Shastra (Template:Circa 100 BC–Template:Circa 350 AD).[3][4] However, the clearest exposition of the sequence arises in the work of Virahanka (Template:Circa 700 AD), whose own work is lost, but is available in a quotation by Gopala (Template:Circa 1135):Template:Sfn

Variations of two earlier meters [is the variation] ... For example, for [a meter of length] four, variations of meters of two [and] three being mixed, five happens. [works out examples 8, 13, 21] ... In this way, the process should be followed in all mātrā-vṛttas [prosodic combinations].Template:Efn

Hemachandra (Template:Circa 1150) is credited with knowledge of the sequence as well,[3] writing that "the sum of the last and the one before the last is the number ... of the next mātrā-vṛtta."Template:Sfn[9]

Europe

File:Liber abbaci magliab f124r.jpg
A page of Fibonacci's Script error: No such module "Lang". from the Biblioteca Nazionale di Firenze showing (in box on right) 13 entries of the Fibonacci sequence:
the indices from present to XII (months) as Latin ordinals and Roman numerals and the numbers (of rabbit pairs) as Hindu-Arabic numerals starting with 1, 2, 3, 5 and ending with 377.

The Fibonacci sequence first appears in the book Script error: No such module "Lang". (The Book of Calculation, 1202) by Fibonacci,Template:Sfn[10] where it is used to calculate the growth of rabbit populations.[11] Fibonacci considers the growth of an idealized (biologically unrealistic) rabbit population, assuming that: a newly born breeding pair of rabbits are put in a field; each breeding pair mates at the age of one month, and at the end of their second month they always produce another pair of rabbits; and rabbits never die, but continue breeding forever. Fibonacci posed the rabbit math problem: how many pairs will there be in one year?

  • At the end of the first month, they mate, but there is still only 1 pair.
  • At the end of the second month they produce a new pair, so there are 2 pairs in the field.
  • At the end of the third month, the original pair produce a second pair, but the second pair only mate to gestate for a month, so there are 3 pairs in all.
  • At the end of the fourth month, the original pair has produced yet another new pair, and the pair born two months ago also produces their first pair, making 5 pairs.

At the end of the Template:Mvar-th month, the number of pairs of rabbits is equal to the number of mature pairs (that is, the number of pairs in month Template:Math) plus the number of pairs alive last month (month Template:Math). The number in the Template:Mvar-th month is the Template:Mvar-th Fibonacci number.[12]

The name "Fibonacci sequence" was first used by the 19th-century number theorist Édouard Lucas.[13]

File:Fibonacci Rabbits.svg
Solution to Fibonacci rabbit problem: In a growing idealized population, the number of rabbit pairs form the Fibonacci sequence. At the end of the nth month, the number of pairs is equal to Fn.

Relation to the golden ratio

Template:Also

Closed-form expression

Like every sequence defined by a homogeneous linear recurrence with constant coefficients, the Fibonacci numbers have a closed-form expression.[14] It has become known as Binet's formula, named after French mathematician Jacques Philippe Marie Binet, though it was already known by Abraham de Moivre and Daniel Bernoulli:[15]

Fn=φnψnφψ=φnψn5,

where Template:Tmath is the golden ratio and Template:Tmath is its conjugate,Template:Sfn

φ=12(1+5)=1.61803,ψ=12(15)=0.61803. The numbers Template:Tmath and Template:Tmath are the two solutions of the quadratic equation Template:Tmath, that is, Template:Tmath, and thus they satisfy the identities Template:Tmath and Template:Tmath.

Since ψ=φ1, Binet's formula can also be written as

Fn=φn(φ)n5=φn(φ)n2φ1.

To see the relation between the sequence and these constants,Template:Sfn note that φ and ψ are also roots of xn=xn1+xn2, so the powers of φ and ψ satisfy the Fibonacci recurrence. In other words,

φn=φn1+φn2,ψn=ψn1+ψn2.

It follows that for any values Template:Mvar and Template:Mvar, the sequence defined by

Un=aφn+bψn

satisfies the same recurrence. If Template:Mvar and Template:Mvar are chosen so that Template:Math and Template:Math then the resulting sequence Template:Math must be the Fibonacci sequence. This is the same as requiring Template:Mvar and Template:Mvar satisfy the system of equations:

aφ0+bψ0=0aφ1+bψ1=1

which has solution

a=1φψ=15,b=a,

producing the required formula.

Taking the starting values Template:Math and Template:Math to be arbitrary constants and solving the system of equations gives the general solution a=U1U0ψ5,b=U0φU15. In particular, choosing Template:Math makes the Template:Mvar-th element of the sequence closely approximate the Template:Mvar-th power of Template:Tmath for large enough values of Template:Mvar. This arises when Template:Math and Template:Math, which produces the sequence of Lucas numbers.

Computation by rounding

Since |ψn5|<12 for all Template:Math, the number Template:Math is the closest integer to φn5. Therefore, it can be found by rounding, using the nearest integer function: Fn=φn5, n0.

In fact, the rounding error quickly becomes very small as Template:Mvar grows, being less than 0.1 for Template:Math, and less than 0.01 for Template:Math. This formula is easily inverted to find an index of a Fibonacci number Template:Mvar: n(F)=logφ5F, F1.

Instead using the floor function gives the largest index of a Fibonacci number that is not greater than Template:Mvar: nlargest(F)=logφ5(F+1/2), F0, where logφ(x)=ln(x)/ln(φ)=log10(x)/log10(φ), ln(φ)=0.481211,[16] and log10(φ)=0.208987.[17]

Magnitude

Since Fn is asymptotic to φn/5, the number of digits in Template:Math is asymptotic to nlog10φ0.2090n. As a consequence, for every integer Template:Math there are either 4 or 5 Fibonacci numbers with Template:Mvar decimal digits.

More generally, in the base Template:Mvar representation, the number of digits in Template:Math is asymptotic to nlogbφ=nlogφlogb.

Limit of consecutive quotients

Johannes Kepler observed that the ratio of consecutive Fibonacci numbers converges. He wrote that "as 5 is to 8 so is 8 to 13, practically, and as 8 is to 13, so is 13 to 21 almost", and concluded that these ratios approach the golden ratio Template:Tmath:[18][19] limnFn+1Fn=φ.

This convergence holds regardless of the starting values U0 and U1, unless U1=U0/φ. This can be verified using Binet's formula. For example, the initial values 3 and 2 generate the sequence 3, 2, 5, 7, 12, 19, 31, 50, 81, 131, 212, 343, 555, ... . The ratio of consecutive elements in this sequence shows the same convergence towards the golden ratio.

In general, limnFn+mFn=φm, because the ratios between consecutive Fibonacci numbers approaches φ.

File:Fibonacci tiling of the plane and approximation to Golden Ratio.gif
Successive tilings of the plane and a graph of approximations to the golden ratio calculated by dividing each Fibonacci number by the previous

Decomposition of powers

Since the golden ratio satisfies the equation φ2=φ+1,

this expression can be used to decompose higher powers φn as a linear function of lower powers, which in turn can be decomposed all the way down to a linear combination of φ and 1. The resulting recurrence relationships yield Fibonacci numbers as the linear coefficients: φn=Fnφ+Fn1. This equation can be proved by induction on Template:Math: φn+1=(Fnφ+Fn1)φ=Fnφ2+Fn1φ=Fn(φ+1)+Fn1φ=(Fn+Fn1)φ+Fn=Fn+1φ+Fn. For ψ=1/φ, it is also the case that ψ2=ψ+1 and it is also the case that ψn=Fnψ+Fn1.

These expressions are also true for Template:Math if the Fibonacci sequence Fn is extended to negative integers using the Fibonacci rule Fn=Fn+2Fn+1.

Identification

Binet's formula provides a proof that a positive integer Template:Mvar is a Fibonacci number if and only if at least one of 5x2+4 or 5x24 is a perfect square.[20] This is because Binet's formula, which can be written as Fn=(φn(1)nφn)/5, can be multiplied by 5φn and solved as a quadratic equation in φn via the quadratic formula:

φn=Fn5±5Fn2+4(1)n2.

Comparing this to φn=Fnφ+Fn1=(Fn5+Fn+2Fn1)/2, it follows that

5Fn2+4(1)n=(Fn+2Fn1)2.

In particular, the left-hand side is a perfect square.

Matrix form

A 2-dimensional system of linear difference equations that describes the Fibonacci sequence is

(Fk+2Fk+1)=(1110)(Fk+1Fk) alternatively denoted Fk+1=𝐀Fk,

which yields Fn=𝐀nF0. The eigenvalues of the matrix Template:Math are φ=12(1+5) and ψ=φ1=12(15) corresponding to the respective eigenvectors μ=(φ1),ν=(φ11).

As the initial value is F0=(10)=15μ15ν, it follows that the Template:Mvarth element is Fn =15Anμ15Anν=15φnμ15(φ)nν=15(1+52)n(φ1)15(152)n(φ11).

From this, the Template:Mvarth element in the Fibonacci series may be read off directly as a closed-form expression: Fn=15(1+52)n15(152)n.

Equivalently, the same computation may be performed by diagonalization of Template:Math through use of its eigendecomposition: A=SΛS1,An=SΛnS1, where Λ=(φ00φ1),S=(φφ111). The closed-form expression for the Template:Mvarth element in the Fibonacci series is therefore given by (Fn+1Fn)=An(F1F0) =SΛnS1(F1F0)=S(φn00(φ)n)S1(F1F0)=(φφ111)(φn00(φ)n)15(1φ11φ)(10), which again yields Fn=φn(φ)n5.

The matrix Template:Math has a determinant of −1, and thus it is a 2 × 2 unimodular matrix.

This property can be understood in terms of the continued fraction representation for the golden ratio Template:Mvar: φ=1+11+11+11+. The convergents of the continued fraction for Template:Mvar are ratios of successive Fibonacci numbers: Template:Math is the Template:Mvar-th convergent, and the Template:Math-st convergent can be found from the recurrence relation Template:Math.[21] The matrix formed from successive convergents of any continued fraction has a determinant of +1 or −1. The matrix representation gives the following closed-form expression for the Fibonacci numbers: (1110)n=(Fn+1FnFnFn1). For a given Template:Mvar, this matrix can be computed in Template:Math arithmetic operations,Template:Efn using the exponentiation by squaring method.

Taking the determinant of both sides of this equation yields Cassini's identity, (1)n=Fn+1Fn1Fn2.

Moreover, since Template:Math for any square matrix Template:Math, the following identities can be derived (they are obtained from two different coefficients of the matrix product, and one may easily deduce the second one from the first one by changing Template:Mvar into Template:Math), FmFn+Fm1Fn1=Fm+n1,FmFn+1+Fm1Fn=Fm+n.

In particular, with Template:Math, F2n1=Fn2+Fn12F2n1=(Fn1+Fn+1)Fn=(2Fn1+Fn)Fn=(2Fn+1Fn)Fn.

These last two identities provide a way to compute Fibonacci numbers recursively in Template:Math arithmetic operations. This matches the time for computing the Template:Mvar-th Fibonacci number from the closed-form matrix formula, but with fewer redundant steps if one avoids recomputing an already computed Fibonacci number (recursion with memoization).[22]

Combinatorial identities

Combinatorial proofs

Most identities involving Fibonacci numbers can be proved using combinatorial arguments using the fact that Fn can be interpreted as the number of (possibly empty) sequences of 1s and 2s whose sum is n1. This can be taken as the definition of Fn with the conventions F0=0, meaning no such sequence exists whose sum is −1, and F1=1, meaning the empty sequence "adds up" to 0. In the following, |...| is the cardinality of a set:

F0=0=|{}|
F1=1=|{()}|
F2=1=|{(1)}|
F3=2=|{(1,1),(2)}|
F4=3=|{(1,1,1),(1,2),(2,1)}|
F5=5=|{(1,1,1,1),(1,1,2),(1,2,1),(2,1,1),(2,2)}|

In this manner the recurrence relation Fn=Fn1+Fn2 may be understood by dividing the Fn sequences into two non-overlapping sets where all sequences either begin with 1 or 2: Fn=|{(1,...),(1,...),...}|+|{(2,...),(2,...),...}| Excluding the first element, the remaining terms in each sequence sum to n2 or n3 and the cardinality of each set is Fn1 or Fn2 giving a total of Fn1+Fn2 sequences, showing this is equal to Fn.

In a similar manner it may be shown that the sum of the first Fibonacci numbers up to the Template:Mvar-th is equal to the Template:Math-th Fibonacci number minus 1.Template:Sfn In symbols: i=1nFi=Fn+21

This may be seen by dividing all sequences summing to n+1 based on the location of the first 2. Specifically, each set consists of those sequences that start (2,...),(1,2,...),..., until the last two sets {(1,1,...,1,2)},{(1,1,...,1)} each with cardinality 1.

Following the same logic as before, by summing the cardinality of each set we see that

Fn+2=Fn+Fn1+...+|{(1,1,...,1,2)}|+|{(1,1,...,1)}|

... where the last two terms have the value F1=1. From this it follows that i=1nFi=Fn+21.

A similar argument, grouping the sums by the position of the first 1 rather than the first 2 gives two more identities: i=0n1F2i+1=F2n and i=1nF2i=F2n+11. In words, the sum of the first Fibonacci numbers with odd index up to F2n1 is the Template:Math-th Fibonacci number, and the sum of the first Fibonacci numbers with even index up to F2n is the Template:Math-th Fibonacci number minus 1.[23]

A different trick may be used to prove i=1nFi2=FnFn+1 or in words, the sum of the squares of the first Fibonacci numbers up to Fn is the product of the Template:Mvar-th and Template:Math-th Fibonacci numbers. To see this, begin with a Fibonacci rectangle of size Fn×Fn+1 and decompose it into squares of size Fn,Fn1,...,F1; from this the identity follows by comparing areas:

File:Fibonacci Squares.svg

Induction proofs

Fibonacci identities often can be easily proved using mathematical induction.

For example, reconsider i=1nFi=Fn+21. Adding Fn+1 to both sides gives

i=1nFi+Fn+1=Fn+1+Fn+21

and so we have the formula for n+1 i=1n+1Fi=Fn+31

Similarly, add Fn+12 to both sides of i=1nFi2=FnFn+1 to give i=1nFi2+Fn+12=Fn+1(Fn+Fn+1) i=1n+1Fi2=Fn+1Fn+2

Binet formula proofs

The Binet formula is 5Fn=φnψn. This can be used to prove Fibonacci identities.

For example, to prove that i=1nFi=Fn+21 note that the left hand side multiplied by 5 becomes 1+φ+φ2++φn(1+ψ+ψ2++ψn)=φn+11φ1ψn+11ψ1=φn+11ψψn+11φ=φn+2+φ+ψn+2ψφψ=φn+2ψn+2(φψ)=5(Fn+21) as required, using the facts φψ=1 and φψ=5 to simplify the equations.

Other identities

Numerous other identities can be derived using various methods. Here are some of them:[24]

Cassini's and Catalan's identities

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Cassini's identity states that Fn2Fn+1Fn1=(1)n1 Catalan's identity is a generalization: Fn2Fn+rFnr=(1)nrFr2

d'Ocagne's identity

FmFn+1Fm+1Fn=(1)nFmn F2n=Fn+12Fn12=Fn(Fn+1+Fn1)=FnLn where Template:Math is the Template:Mvar-th Lucas number. The last is an identity for doubling Template:Mvar; other identities of this type are F3n=2Fn3+3FnFn+1Fn1=5Fn3+3(1)nFn by Cassini's identity.

F3n+1=Fn+13+3Fn+1Fn2Fn3 F3n+2=Fn+13+3Fn+12Fn+Fn3 F4n=4FnFn+1(Fn+12+2Fn2)3Fn2(Fn2+2Fn+12) These can be found experimentally using lattice reduction, and are useful in setting up the special number field sieve to factorize a Fibonacci number.

More generally,[24]

Fkn+c=i=0k(ki)FciFniFn+1ki.

or alternatively

Fkn+c=i=0k(ki)Fc+iFniFn1ki.

Putting Template:Math in this formula, one gets again the formulas of the end of above section Matrix form.

Generating function

The ordinary generating function of the Fibonacci sequence is the power series

s(z)=k=0Fkzk=0+z+z2+2z3+3z4+5z5+.

This series is convergent for any complex number z satisfying |z|<1/φ0.618, and its sum has a simple closed form:[25]

s(z)=z1zz2.

This can be proved by multiplying by (1zz2): (1zz2)s(z)=k=0Fkzkk=0Fkzk+1k=0Fkzk+2=k=0Fkzkk=1Fk1zkk=2Fk2zk=0z0+1z10z1+k=2(FkFk1Fk2)zk=z,

where all terms involving zk for k2 cancel out because of the defining Fibonacci recurrence relation.

The partial fraction decomposition is given by s(z)=15(11φz11ψz) where φ=12(1+5) is the golden ratio and ψ=12(15) is its conjugate.

Using z equal to any of 0.01, 0.001, 0.0001, etc. lays out the first Fibonacci numbers in the decimal expansion of s(z). For example, s(0.001)=0.0010.998999=1000998999=0.001001002003005008013021.

Reciprocal sums

Infinite sums over reciprocal Fibonacci numbers can sometimes be evaluated in terms of theta functions. For example, the sum of every odd-indexed reciprocal Fibonacci number can be written as k=11F2k1=54ϑ2(0,352)2,

and the sum of squared reciprocal Fibonacci numbers as k=11Fk2=524(ϑ2(0,352)4ϑ4(0,352)4+1).

If we add 1 to each Fibonacci number in the first sum, there is also the closed form k=111+F2k1=52,

and there is a nested sum of squared Fibonacci numbers giving the reciprocal of the golden ratio, k=1(1)k+1j=1kFj2=512.

The sum of all even-indexed reciprocal Fibonacci numbers is[26] k=11F2k=5(L(ψ2)L(ψ4)) with the Lambert series L(q):=k=1qk1qk, since 1F2k=5(ψ2k1ψ2kψ4k1ψ4k).

So the reciprocal Fibonacci constant is[27] k=11Fk=k=11F2k1+k=11F2k=3.359885666243

Moreover, this number has been proved irrational by Richard André-Jeannin.[28]

Millin's series gives the identity[29] k=01F2k=752, which follows from the closed form for its partial sums as Template:Mvar tends to infinity: k=0N1F2k=3F2N1F2N.

Primes and divisibility

Divisibility properties

Every third number of the sequence is even (a multiple of F3=2) and, more generally, every Template:Mvar-th number of the sequence is a multiple of Fk. Thus the Fibonacci sequence is an example of a divisibility sequence. In fact, the Fibonacci sequence satisfies the stronger divisibility property[30][31] gcd(Fa,Fb,Fc,)=Fgcd(a,b,c,) where Template:Math is the greatest common divisor function. (This relation is different if a different indexing convention is used, such as the one that starts the sequence with Template:Tmath and Template:Tmath.)

In particular, any three consecutive Fibonacci numbers are pairwise coprime because both F1=1 and F2=1. That is,

gcd(Fn,Fn+1)=gcd(Fn,Fn+2)=gcd(Fn+1,Fn+2)=1

for every Template:Mvar.

Every prime number Template:Mvar divides a Fibonacci number that can be determined by the value of Template:Mvar modulo 5. If Template:Mvar is congruent to 1 or 4 modulo 5, then Template:Mvar divides Template:Math, and if Template:Mvar is congruent to 2 or 3 modulo 5, then, Template:Mvar divides Template:Math. The remaining case is that Template:Math, and in this case Template:Mvar divides Fp.

{p=5pFp,p±1(mod5)pFp1,p±2(mod5)pFp+1.

These cases can be combined into a single, non-piecewise formula, using the Legendre symbol:[32] pFp(5p).

Primality testing

The above formula can be used as a primality test in the sense that if nFn(5n), where the Legendre symbol has been replaced by the Jacobi symbol, then this is evidence that Template:Mvar is a prime, and if it fails to hold, then Template:Mvar is definitely not a prime. If Template:Mvar is composite and satisfies the formula, then Template:Mvar is a Fibonacci pseudoprime. When Template:Mvar is largeTemplate:Sndsay a 500-bit numberTemplate:Sndthen we can calculate Template:Math efficiently using the matrix form. Thus

(Fm+1FmFmFm1)(1110)m(modn). Here the matrix power Template:Math is calculated using modular exponentiation, which can be adapted to matrices.[33]

Fibonacci primes

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A Fibonacci prime is a Fibonacci number that is prime. The first few are:[34]

2, 3, 5, 13, 89, 233, 1597, 28657, 514229, ...

Fibonacci primes with thousands of digits have been found, but it is not known whether there are infinitely many.[35]

Template:Math is divisible by Template:Math, so, apart from Template:Math, any Fibonacci prime must have a prime index. As there are arbitrarily long runs of composite numbers, there are therefore also arbitrarily long runs of composite Fibonacci numbers.

No Fibonacci number greater than Template:Math is one greater or one less than a prime number.[36]

The only nontrivial square Fibonacci number is 144.[37] Attila Pethő proved in 2001 that there is only a finite number of perfect power Fibonacci numbers.[38] In 2006, Y. Bugeaud, M. Mignotte, and S. Siksek proved that 8 and 144 are the only such non-trivial perfect powers.[39]

1, 3, 21, and 55 are the only triangular Fibonacci numbers, which was conjectured by Vern Hoggatt and proved by Luo Ming.[40]

No Fibonacci number can be a perfect number.[41] More generally, no Fibonacci number other than 1 can be multiply perfect,[42] and no ratio of two Fibonacci numbers can be perfect.[43]

Prime divisors

With the exceptions of 1, 8 and 144 (Template:Math, Template:Math and Template:Math) every Fibonacci number has a prime factor that is not a factor of any smaller Fibonacci number (Carmichael's theorem).[44] As a result, 8 and 144 (Template:Math and Template:Math) are the only Fibonacci numbers that are the product of other Fibonacci numbers.[45]

The divisibility of Fibonacci numbers by a prime Template:Mvar is related to the Legendre symbol (p5) which is evaluated as follows: (p5)={0if p=51if p±1(mod5)1if p±2(mod5).

If Template:Mvar is a prime number then Fp(p5)(modp)andFp(p5)0(modp).[46]Template:Sfn

For example, (25)=1,F3=2,F2=1,(35)=1,F4=3,F3=2,(55)=0,F5=5,(75)=1,F8=21,F7=13,(115)=+1,F10=55,F11=89.

It is not known whether there exists a prime Template:Mvar such that

Fp(p5)0(modp2).

Such primes (if there are any) would be called Wall–Sun–Sun primes.

Also, if Template:Math is an odd prime number then:Template:Sfn 5Fp±122{12(5(p5)±5)(modp)if p1(mod4)12(5(p5)3)(modp)if p3(mod4).

Example 1. Template:Math, in this case Template:Math and we have: (75)=1:12(5(75)+3)=1,12(5(75)3)=4. F3=2 and F4=3. 5F32=201(mod7) and 5F42=454(mod7)

Example 2. Template:Math, in this case Template:Math and we have: (115)=+1:12(5(115)+3)=4,12(5(115)3)=1. F5=5 and F6=8. 5F52=1254(mod11) and 5F62=3201(mod11)

Example 3. Template:Math, in this case Template:Math and we have: (135)=1:12(5(135)5)=5,12(5(135)+5)=0. F6=8 and F7=13. 5F62=3205(mod13) and 5F72=8450(mod13)

Example 4. Template:Math, in this case Template:Math and we have: (295)=+1:12(5(295)5)=0,12(5(295)+5)=5. F14=377 and F15=610. 5F142=7106450(mod29) and 5F152=18605005(mod29)

For odd Template:Mvar, all odd prime divisors of Template:Math are congruent to 1 modulo 4, implying that all odd divisors of Template:Math (as the products of odd prime divisors) are congruent to 1 modulo 4.Template:Sfn

For example, F1=1, F3=2, F5=5, F7=13, F9=34=217, F11=89, F13=233, F15=610=2561.

All known factors of Fibonacci numbers Template:Math for all Template:Math are collected at the relevant repositories.[47][48]

Periodicity modulo n

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If the members of the Fibonacci sequence are taken mod Template:Mvar, the resulting sequence is periodic with period at most Template:Math.[49] The lengths of the periods for various Template:Mvar form the so-called Pisano periods.[50] Determining a general formula for the Pisano periods is an open problem, which includes as a subproblem a special instance of the problem of finding the multiplicative order of a modular integer or of an element in a finite field. However, for any particular Template:Mvar, the Pisano period may be found as an instance of cycle detection.

Generalizations

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The Fibonacci sequence is one of the simplest and earliest known sequences defined by a recurrence relation, and specifically by a linear difference equation. All these sequences may be viewed as generalizations of the Fibonacci sequence. In particular, Binet's formula may be generalized to any sequence that is a solution of a homogeneous linear difference equation with constant coefficients.

Some specific examples that are close, in some sense, to the Fibonacci sequence include:

Applications

Mathematics

File:Pascal triangle fibonacci.svg
The Fibonacci numbers are the sums of the diagonals (shown in red) of a left-justified Pascal's triangle.

The Fibonacci numbers occur as the sums of binomial coefficients in the "shallow" diagonals of Pascal's triangle:Template:Sfn Fn=k=0n12(nk1k). This can be proved by expanding the generating function x1xx2=x+x2(1+x)+x3(1+x)2++xk+1(1+x)k+=n=0Fnxn and collecting like terms of xn.

To see how the formula is used, we can arrange the sums by the number of terms present:

Template:Math Template:Math
Template:Math Template:Math Template:Math Template:Math
Template:Math Template:Math Template:Math

which is (50)+(41)+(32), where we are choosing the positions of Template:Mvar twos from Template:Math terms.

File:Fibonacci climbing stairs.svg
Use of the Fibonacci sequence to count {1, 2}-restricted compositions

These numbers also give the solution to certain enumerative problems,[52] the most common of which is that of counting the number of ways of writing a given number Template:Mvar as an ordered sum of 1s and 2s (called compositions); there are Template:Math ways to do this (equivalently, it's also the number of domino tilings of the 2×n rectangle). For example, there are Template:Math ways one can climb a staircase of 5 steps, taking one or two steps at a time:

Template:Math Template:Math Template:Math Template:Math Template:Math Template:Math
Template:Math Template:Math Template:Math

The figure shows that 8 can be decomposed into 5 (the number of ways to climb 4 steps, followed by a single-step) plus 3 (the number of ways to climb 3 steps, followed by a double-step). The same reasoning is applied recursively until a single step, of which there is only one way to climb.

The Fibonacci numbers can be found in different ways among the set of binary strings, or equivalently, among the subsets of a given set.

Computer science

File:Fibonacci Tree 6.svg
Fibonacci tree of height 6. Balance factors green; heights red.
The keys in the left spine are Fibonacci numbers.

Nature

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File:FibonacciChamomile.PNG
Yellow chamomile head showing the arrangement in 21 (blue) and 13 (cyan) spirals. Such arrangements involving consecutive Fibonacci numbers appear in a wide variety of plants.

Fibonacci sequences appear in biological settings,[62] such as branching in trees, arrangement of leaves on a stem, the fruitlets of a pineapple,[63] the flowering of artichoke, the leaves of the spiral aloe[64] (Aloe polyphylla), the arrangement of a pine cone,[65] and the family tree of honeybees.[66][67] Kepler pointed out the presence of the Fibonacci sequence in nature, using it to explain the (golden ratio-related) pentagonal form of some flowers.Template:Sfn Field daisies most often have petals in counts of Fibonacci numbers.Template:Sfn In 1830, Karl Friedrich Schimper and Alexander Braun discovered that the parastichies (spiral phyllotaxis) of plants were frequently expressed as fractions involving Fibonacci numbers.[68]

Przemysław Prusinkiewicz advanced the idea that real instances can in part be understood as the expression of certain algebraic constraints on free groups, specifically as certain Lindenmayer grammars.[69]

File:SunflowerModel.svg
Illustration of Vogel's model for Template:Math

A model for the pattern of florets in the head of a sunflower was proposed by Template:Ill in 1979.[70] This has the form

θ=2πφ2n, r=cn

where Template:Mvar is the index number of the floret and Template:Mvar is a constant scaling factor; the florets thus lie on Fermat's spiral. The divergence angle, approximately 137.51°, is the golden angle, dividing the circle in the golden ratio. Because this ratio is irrational, no floret has a neighbor at exactly the same angle from the center, so the florets pack efficiently. Because the rational approximations to the golden ratio are of the form Template:Math, the nearest neighbors of floret number Template:Mvar are those at Template:Math for some index Template:Mvar, which depends on Template:Mvar, the distance from the center. Sunflowers and similar flowers most commonly have spirals of florets in clockwise and counter-clockwise directions in the amount of adjacent Fibonacci numbers,Template:Sfn typically counted by the outermost range of radii.[71]

Fibonacci numbers also appear in the ancestral pedigrees of bees (which are haplodiploids), according to the following rules:

  • If an egg is laid but not fertilized, it produces a male (or drone bee in honeybees).
  • If, however, an egg is fertilized, it produces a female.

Thus, a male bee always has one parent, and a female bee has two. If one traces the pedigree of any male bee (1 bee), he has 1 parent (1 bee), 2 grandparents, 3 great-grandparents, 5 great-great-grandparents, and so on. This sequence of numbers of parents is the Fibonacci sequence. The number of ancestors at each level, Template:Math, is the number of female ancestors, which is Template:Math, plus the number of male ancestors, which is Template:Math.[72][73] This is under the unrealistic assumption that the ancestors at each level are otherwise unrelated.

File:X chromosome ancestral line Fibonacci sequence.svg
The number of possible ancestors on the X chromosome inheritance line at a given ancestral generation follows the Fibonacci sequence. (After Hutchison, L. "Growing the Family Tree: The Power of DNA in Reconstructing Family Relationships".[74])

It has similarly been noticed that the number of possible ancestors on the human X chromosome inheritance line at a given ancestral generation also follows the Fibonacci sequence.[74] A male individual has an X chromosome, which he received from his mother, and a Y chromosome, which he received from his father. The male counts as the "origin" of his own X chromosome (F1=1), and at his parents' generation, his X chromosome came from a single parent (F2=1). The male's mother received one X chromosome from her mother (the son's maternal grandmother), and one from her father (the son's maternal grandfather), so two grandparents contributed to the male descendant's X chromosome (F3=2). The maternal grandfather received his X chromosome from his mother, and the maternal grandmother received X chromosomes from both of her parents, so three great-grandparents contributed to the male descendant's X chromosome (F4=3). Five great-great-grandparents contributed to the male descendant's X chromosome (F5=5), etc. (This assumes that all ancestors of a given descendant are independent, but if any genealogy is traced far enough back in time, ancestors begin to appear on multiple lines of the genealogy, until eventually a population founder appears on all lines of the genealogy.)

Other

  • In optics, when a beam of light shines at an angle through two stacked transparent plates of different materials of different refractive indexes, it may reflect off three surfaces: the top, middle, and bottom surfaces of the two plates. The number of different beam paths that have Template:Mvar reflections, for Template:Math, is the Template:Mvar-th Fibonacci number. (However, when Template:Math, there are three reflection paths, not two, one for each of the three surfaces.)Template:Sfn
  • Fibonacci retracement levels are widely used in technical analysis for financial market trading.
  • Since the conversion factor 1.609344 for miles to kilometers is close to the golden ratio, the decomposition of distance in miles into a sum of Fibonacci numbers becomes nearly the kilometer sum when the Fibonacci numbers are replaced by their successors. This method amounts to a radix 2 number register in golden ratio base Template:Mvar being shifted. To convert from kilometers to miles, shift the register down the Fibonacci sequence instead.[75]
  • The measured values of voltages and currents in the infinite resistor chain circuit (also called the resistor ladder or infinite series-parallel circuit) follow the Fibonacci sequence. The intermediate results of adding the alternating series and parallel resistances yields fractions composed of consecutive Fibonacci numbers. The equivalent resistance of the entire circuit equals the golden ratio.[76]
  • Brasch et al. 2012 show how a generalized Fibonacci sequence also can be connected to the field of economics.[77] In particular, it is shown how a generalized Fibonacci sequence enters the control function of finite-horizon dynamic optimisation problems with one state and one control variable. The procedure is illustrated in an example often referred to as the Brock–Mirman economic growth model.
  • Mario Merz included the Fibonacci sequence in some of his artworks beginning in 1970.Template:Sfn
  • Joseph Schillinger (1895–1943) developed a system of composition which uses Fibonacci intervals in some of its melodies; he viewed these as the musical counterpart to the elaborate harmony evident within nature.Template:Sfn See also Template:Slink.
  • In software development, Fibonacci numbers are often used by agile teams operating under the Scrum framework to size their product backlog items.[78]

See also

References

Explanatory footnotes

Template:Notelist

Citations

Template:Reflist

Works cited

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External links

Template:Sister project Template:Sister project

Template:Classes of natural numbers Template:Metallic ratios Template:Series (mathematics) Template:Fibonacci Template:Authority control Template:Interwiki extra

  1. Richard A. Brualdi, Introductory Combinatorics, Fifth edition, Pearson, 2005
  2. Peter Cameron, Combinatorics: Topics, Techniques, Algorithms, Cambridge University Press, 1994
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  73. Yanega, D. 1996. Sex ratio and sex allocation in sweat bees (Hymenoptera: Halictidae). J. Kans. Ent. Soc. 69 Suppl.: 98-115.
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