Polygamma function

File:Mplwp polygamma03.svg

Graphs of the polygamma functions ψ, ψ⁽¹⁾, ψ⁽²⁾ and ψ⁽³⁾ of real arguments

Plot of the digamma function, the first polygamma function, in the complex plane, with colors showing one cycle of phase shift around each pole and zero

Plot of the digamma function, the first polygamma function, in the complex plane from −2−2i to 2+2i with colors created by Mathematica's function ComplexPlot3D showing one cycle of phase shift around each pole and the zero

In mathematics, the polygamma function of order Template:Mvar is a meromorphic function on the complex numbers $\mathbb{ℂ}$ defined as the (m + 1)th derivative of the logarithm of the gamma function:

${\psi }^{(m)}(z):=\frac{{\mathrm{d}}^m}{\mathrm{d}{z}^m}\psi (z)=\frac{{\mathrm{d}}^{m+1}}{\mathrm{d}{z}^{m+1}}\ln \mathrm{\Gamma }(z).$

Thus

${\psi }^{(0)}(z)=\psi (z)=\frac{{\mathrm{\Gamma }}^{\prime }(z)}{\mathrm{\Gamma }(z)}$

holds where ψ(z) is the digamma function and Γ(z) is the gamma function. They are holomorphic on $\mathbb{ℂ}\mathrm{\setminus }{\mathbb{\mathbb{Z}}}_{\le 0}$. At all the nonpositive integers these polygamma functions have a pole of order m + 1. The function ψ⁽¹⁾(z) is sometimes called the trigamma function.

The logarithm of the gamma function and the first few polygamma functions in the complex plane

File:Complex LogGamma.jpg	File:Complex Polygamma 0.jpg	File:Complex Polygamma 1.jpg
ln Γ(z)	ψ(0)(z)	ψ(1)(z)
File:Complex Polygamma 2.jpg	File:Complex Polygamma 3.jpg	File:Complex Polygamma 4.jpg
ψ(2)(z)	ψ(3)(z)	ψ(4)(z)

Integral representation

When m > 0 and Re z > 0, the polygamma function equals

$\begin{array}{rl}{\psi }^{(m)}(z)& =(-1{)}^{m+1}\underset{0}{\overset{\mathrm{\infty }}{\int }}\frac{t^m{e}^{-zt}}{1-e^{-t}}\mathrm{d}t\\ & =-\underset{0}{\overset{1}{\int }}\frac{t^{z-1}}{1-t}(\ln t{)}^m\mathrm{d}t\\ & =(-1{)}^{m+1}m!\zeta (m+1,z)\end{array}$

where $\zeta (s,q)$ is the Hurwitz zeta function.

This expresses the polygamma function as the Laplace transform of Template:Sfrac. It follows from Bernstein's theorem on monotone functions that, for m > 0 and x real and non-negative, (−1)^m+1 ψ^(m)(x) is a completely monotone function.

Setting m = 0 in the above formula does not give an integral representation of the digamma function. The digamma function has an integral representation, due to Gauss, which is similar to the m = 0 case above but which has an extra term Template:Sfrac.

Recurrence relation

It satisfies the recurrence relation

${\psi }^{(m)}(z+1)={\psi }^{(m)}(z)+\frac{(-1{)}^{m}m!}{z^{m+1}}$

which – considered for positive integer argument – leads to a presentation of the sum of reciprocals of the powers of the natural numbers:

$\frac{{\psi }^{(m)}(n)}{(-1{)}^{m+1}m!}=\zeta (1+m)-\sum _{k=1}^{n-1}\frac{1}{k^{m+1}}=\sum _{k=n}^{\mathrm{\infty }}\frac{1}{k^{m+1}}m\ge 1$

and

${\psi }^{(0)}(n)=-\gamma +\sum _{k=1}^{n-1}\frac{1}{k}$

for all $n\in \mathbb{\mathbb{N}}$, where $\gamma$ is the Euler–Mascheroni constant. Like the log-gamma function, the polygamma functions can be generalized from the domain $\mathbb{\mathbb{N}}$ uniquely to positive real numbers only due to their recurrence relation and one given function-value, say ψ^(m)(1), except in the case m = 0 where the additional condition of strict monotonicity on ${\mathbb{ℝ}}^{+}$ is still needed. This is a trivial consequence of the Bohr–Mollerup theorem for the gamma function where strictly logarithmic convexity on ${\mathbb{ℝ}}^{+}$ is demanded additionally. The case m = 0 must be treated differently because ψ⁽⁰⁾ is not normalizable at infinity (the sum of the reciprocals doesn't converge).

Reflection relation

$(-1{)}^m{\psi }^{(m)}(1-z)-{\psi }^{(m)}(z)=\pi \frac{{\mathrm{d}}^m}{\mathrm{d}{z}^m}\cot \pi z={\pi }^{m+1}\frac{P_m(\cos \pi z)}{{\sin }^{m+1}(\pi z)}$

where P_m is alternately an odd or even polynomial of degree Template:Abs with integer coefficients and leading coefficient (−1)^m⌈2^{m − 1}⌉. They obey the recursion equation

$\begin{array}{rl}{P}_0(x)& =x\\ P_{m+1}(x)& =-((m+1)x{P}_m(x)+(1-x^2)P{\text{'}}_m(x)).\end{array}$

Multiplication theorem

The multiplication theorem gives

$k^{m+1}{\psi }^{(m)}(kz)=\sum _{n=0}^{k-1}{\psi }^{(m)}(z+\frac{n}{k})m\ge 1$

and

$k{\psi }^{(0)}(kz)=k\ln k+\sum _{n=0}^{k-1}{\psi }^{(0)}(z+\frac{n}{k})$

for the digamma function.

Series representation

The polygamma function has the series representation

${\psi }^{(m)}(z)=(-1{)}^{m+1}m!\sum _{k=0}^{\mathrm{\infty }}\frac{1}{(z+k{)}^{m+1}}$

which holds for integer values of m > 0 and any complex Template:Mvar not equal to a negative integer. This representation can be written more compactly in terms of the Hurwitz zeta function as

${\psi }^{(m)}(z)=(-1{)}^{m+1}m!\zeta (m+1,z).$

This relation can for example be used to compute the special values

${\psi }^{(2n-1)}\left(\frac{1}{4}\right)=\frac{4^{2n-1}}{2n}({\pi }^{2n}(2^{2n}-1)|B_{2n}|+2(2n)!\beta (2n));$

${\psi }^{(2n-1)}\left(\frac{3}{4}\right)=\frac{4^{2n-1}}{2n}({\pi }^{2n}(2^{2n}-1)|B_{2n}|-2(2n)!\beta (2n));$

${\psi }^{(2n)}\left(\frac{1}{4}\right)=-2^{2n-1}({\pi }^{2n+1}|E_{2n}|+2(2n)!(2^{2n+1}-1)\zeta (2n+1));$

${\psi }^{(2n)}\left(\frac{3}{4}\right)=2^{2n-1}({\pi }^{2n+1}|E_{2n}|-2(2n)!(2^{2n+1}-1)\zeta (2n+1)).$

Alternately, the Hurwitz zeta can be understood to generalize the polygamma to arbitrary, non-integer order.

One more series may be permitted for the polygamma functions. As given by Schlömilch,

$\frac{1}{\mathrm{\Gamma }(z)}=z{e}^{\gamma z}\prod _{n=1}^{\mathrm{\infty }}(1+\frac{z}{n})e^{-\frac{z}{n}}.$

This is a result of the Weierstrass factorization theorem. Thus, the gamma function may now be defined as:

$\mathrm{\Gamma }(z)=\frac{e^{-\gamma z}}{z}\prod _{n=1}^{\mathrm{\infty }}{(1+\frac{z}{n})}^{-1}{e}^{\frac{z}{n}}.$

Now, the natural logarithm of the gamma function is easily representable:

$\ln \mathrm{\Gamma }(z)=-\gamma z-\ln (z)+\sum _{k=1}^{\mathrm{\infty }}(\frac{z}{k}-\ln (1+\frac{z}{k})).$

Finally, we arrive at a summation representation for the polygamma function:

${\psi }^{(n)}(z)=\frac{{\mathrm{d}}^{n+1}}{\mathrm{d}{z}^{n+1}}\ln \mathrm{\Gamma }(z)=-\gamma {\delta }_{n0}-\frac{(-1{)}^{n}n!}{z^{n+1}}+\sum _{k=1}^{\mathrm{\infty }}(\frac{1}{k}{\delta }_{n0}-\frac{(-1{)}^{n}n!}{(k+z{)}^{n+1}})$

Where δ_n0 is the Kronecker delta.

Also the Lerch transcendent

$\mathrm{\Phi }(-1,m+1,z)=\sum _{k=0}^{\mathrm{\infty }}\frac{(-1{)}^k}{(z+k{)}^{m+1}}$

can be denoted in terms of polygamma function

$\mathrm{\Phi }(-1,m+1,z)=\frac{1}{(-2{)}^{m+1}m!}({\psi }^{(m)}\left(\frac{z}{2}\right)-{\psi }^{(m)}\left(\frac{z+1}{2}\right))$

Taylor series

The Taylor series at z = -1 is

${\psi }^{(m)}(z+1)=\sum _{k=0}^{\mathrm{\infty }}(-1{)}^{m+k+1}\frac{(m+k)!}{k!}\zeta (m+k+1)z^{k}m\ge 1$

and

${\psi }^{(0)}(z+1)=-\gamma +\sum _{k=1}^{\mathrm{\infty }}(-1{)}^{k+1}\zeta (k+1)z^k$

which converges for Template:Abs < 1. Here, Template:Mvar is the Riemann zeta function. This series is easily derived from the corresponding Taylor series for the Hurwitz zeta function. This series may be used to derive a number of rational zeta series.

Asymptotic expansion

These non-converging series can be used to get quickly an approximation value with a certain numeric at-least-precision for large arguments:

${\psi }^{(m)}(z)\sim (-1{)}^{m+1}\sum _{k=0}^{\mathrm{\infty }}\frac{(k+m-1)!}{k!}\frac{B_k}{z^{k+m}}m\ge 1$

and

${\psi }^{(0)}(z)\sim \ln (z)-\sum _{k=1}^{\mathrm{\infty }}\frac{B_k}{k{z}^k}$

where we have chosen B₁ = Template:Sfrac, i.e. the Bernoulli numbers of the second kind.

Inequalities

The hyperbolic cotangent satisfies the inequality

$\frac{t}{2}\coth \frac{t}{2}\ge 1,$

and this implies that the function

$\frac{t^m}{1-e^{-t}}-(t^{m-1}+\frac{t^m}{2})$

is non-negative for all m ≥ 1 and t ≥ 0. It follows that the Laplace transform of this function is completely monotone. By the integral representation above, we conclude that

$(-1{)}^{m+1}{\psi }^{(m)}(x)-(\frac{(m-1)!}{x^m}+\frac{m!}{2x^{m+1}})$

is completely monotone. The convexity inequality e^t ≥ 1 + t implies that

$(t^{m-1}+t^m)-\frac{t^m}{1-e^{-t}}$

is non-negative for all m ≥ 1 and t ≥ 0, so a similar Laplace transformation argument yields the complete monotonicity of

$(\frac{(m-1)!}{x^m}+\frac{m!}{x^{m+1}})-(-1{)}^{m+1}{\psi }^{(m)}(x).$

Therefore, for all m ≥ 1 and x > 0,

$\frac{(m-1)!}{x^m}+\frac{m!}{2x^{m+1}}\le (-1{)}^{m+1}{\psi }^{(m)}(x)\le \frac{(m-1)!}{x^m}+\frac{m!}{x^{m+1}}.$

Since both bounds are strictly positive for $x>0$, we have:

• $\ln \mathrm{\Gamma }(x)$ is strictly convex.
• For $m=0$, the digamma function, $\psi (x)={\psi }^{(0)}(x)$, is strictly monotonic increasing and strictly concave.
• For $m$ odd, the polygamma functions, ${\psi }^{(1)},{\psi }^{(3)},{\psi }^{(5)},\dots$, are strictly positive, strictly monotonic decreasing and strictly convex.
• For $m$ even the polygamma functions, ${\psi }^{(2)},{\psi }^{(4)},{\psi }^{(6)},\dots$, are strictly negative, strictly monotonic increasing and strictly concave.

This can be seen in the first plot above.

Trigamma bounds and asymptote

For the case of the trigamma function ($m=1$) the final inequality formula above for $x>0$, can be rewritten as:

$\frac{x+\frac{1}{2}}{x^2}\le {\psi }^{(1)}(x)\le \frac{x+1}{x^2}$

so that for $x\gg 1$: ${\psi }^{(1)}(x)\approx \frac{1}{x}$.

See also

• Factorial
• Gamma function
• Digamma function
• Trigamma function
• Generalized polygamma function