Translational symmetry: Revision history

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23 May 2025

  • curprev 18:2918:29, 23 May 2025 18.29.210.141 talk 6,745 bytes +6,745 In this example, the domain of f should be the power set of R^2 (not R^2 itself), and then in the Lebesgue measure the domain is actually the measurable sets, not the whole power set. But maybe this is too much for a footnote of the cartoon, so let us not specify the domain and image of f.
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